Answer:
ac = 72 m/s²
Fc = 504 N
Explanation:
We can find the centripetal acceleration of the hammer by using the following formula:

where,
ac = centripetal acceleration = ?
v = constant speed = 12 m/s
r = radius = 2 m
Therefore,

<u>ac = 72 m/s²</u>
<u></u>
Now, the centripetal force applied by the athlete on the hammer will be:

<u>Fc = 504 N</u>
Answer:
No, not necessarily
Explanation:
If an object is moving with an acceleration that causes its speed to be reduced, there will be a moment in which it reaches v = 0, but this doesn't necessarily mean that the acceleration isn't acting anymore. If the object continues its movement with the same acceleration, it's velocity will become negative.
An example of an object that has zero velocity but non-zero acceleration:
If you throw an object in the air with a certain velocity, it will move vertically, reducing its velocity in a 9,8
rate (which is the acceleration caused by gravity). At a certain point, the object will reach its maximum height, and will start to fall. In the exact moment that it reaches the maximum height, before it starts falling, its velocity is zero, but gravity is still acting on the object (this is the reason why it starts falling instead of just being stopped at that point). Therefore, at that point, the object has zero velocity but an acceleration of 9,8
.
Answer:
weight = 25*10 =250 N
Explanation:
g must be given in units of m/s^2
The weight of any type of body will be the product of his mass by the gravity
where:
m =mass [kg]
F = force [N] or [kg*m/s^2]
g = acceleration [m/s^2]
B) Not work since decrease in temperature wouldnt cause evaporation or reverse in cycle.
Answer:
The current will be increased and also for the resistance.
Explanation:
The analysis of a direct current circuit can give us the explanation we need. Using the ohm law, which tells us that the voltage is equal to the product of the current by the resistance we have:
![V=I*R\\where\\V= voltage [V]\\I= amperes [amp]\\R=resistance [ohm]\\](https://tex.z-dn.net/?f=V%3DI%2AR%5C%5Cwhere%5C%5CV%3D%20voltage%20%5BV%5D%5C%5CI%3D%20amperes%20%5Bamp%5D%5C%5CR%3Dresistance%20%5Bohm%5D%5C%5C)
The voltage is equal to the potential difference therefore we will have these expressions:

If we increase the potential differential or circuit voltage, the current will also increase and so does the resistance by increasing the voltage. If we put numerical values in the equation given before, we can confirm this fact.