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OLga [1]
3 years ago
15

Roughly how many stars are in the Milky Way Galaxy?

Physics
2 answers:
svetlana [45]3 years ago
7 0

Answer:

there are many stars in the milky way galaky

Explanation:

uncountable stars

Masja [62]3 years ago
7 0

Answer:

there are 100 billion to 400 billion star in milky way galaxy

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According to the graph, what is the motorcycle’s Average velocity ?
borishaifa [10]
According to the position vs time graph, the <em>average</em> <em>velocity</em> of the motorcycle is the change in position divided by the change in time. Also, note that the slope is linear and positive throughout the 5 hours, it doesn't change direction. 

Therefore, we have
Avg velocity = change in direction/change in time
Avg velocity = (150km - 30km)/(5h - 0h)
Avg velocity = 24km/hr south. 

3 0
3 years ago
1) A train accelerates from 36 km/hr to 54 km/hr in 10<br> s. Find acceleration?
Crank

Answer: Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled 125m

Hope it helps you

3 0
4 years ago
What are the units for speed
nexus9112 [7]
Speed has the dimensions of distance divided by time. The SI unit of speed is themetre<span> per second, but the most common unit of speed in everyday usage is the kilometre per </span>hour<span> or, in the US and the UK, miles per </span>hour<span>. For air and marine travel the knot is commonly used.</span>
8 0
3 years ago
Read 2 more answers
50POINTS! Find the orbital speed of a satellite in a circular orbit 1700km above the surface of the Earth. M_earth 5.97e24kg, r_
ivolga24 [154]
<h2>Answer: 7020.117 m/s</h2>

Explanation:

The velocity of a satellite describing a circular orbit is<u> constant</u> and defined by the following expression:  

V=\sqrt{G\frac{M}{R}} (1)  

Where:  

G=6.674({10}^{-11})\frac{N{m}^{2}}{{kg}^{2}} is the gravity constant

M_{Earth}=5.97{10}^{24}kg the mass of the massive body around which the satellite is orbiting, in this case, the Earth .

R=r_{Earth}+h=8080000m the radius of the orbit (measured from the center of the planet to the satellite).  

This means the radius of the orbit is equal to <u>the sum</u> of the average radius of the Earth r_{Earth} and the altitude of the satellite above the Earth's surface h.

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. It depends on the mass of the massive body (the Earth).

Now, rewriting equation (1) with the known values:

V=\sqrt{(6.674({10}^{-11})\frac{N{m}^{2}}{{kg}^{2}})\frac{5.97{10}^{24}kg}{8080000m}}

V=7020.117\frac{m}{s}  

6 0
4 years ago
Read 2 more answers
Determine the wavelength of incident electromagnetic radiation required to cause an electron transition from the n = 5 to the n
ollegr [7]
The correct answer is: wavelength = 4562 nm

Explanation:

Rydberg's formula is given as:
\frac{1}{\lambda} = R[ \frac{1}{n_1^2}  - \frac{1}{n_2^2} ] --- (1)

Where 
R = Rydberg's constant = 1.096 * 10^7 per meter
n_1 = 5
n_2 = 7

λ = Wavelength

Plug in the values in (1):

(1)=> \frac{1}{\lambda} = (1.096 * 10^7)[ \frac{1}{5^2} - \frac{1}{7^2} ]

\frac{1}{\lambda} = (1.096 * 10^7)[ 0.04 - 0.020 ] \\ \lambda =  \frac{1}{(1.096 * 10^7)[0.020 ]} \\ \lambda = 4562 nm
8 0
3 years ago
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