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Answer:
= 0.014 g of BaCO3
Explanation:
Let x = mol/L of BaCO3 that dissolve.
This will give;
x mol/L Ba2+ and x mol/L CO32-
But;
Ksp = 5.1x10^-9.
Therefore;
Ksp = 5.1 x 10^-9 = (x)(x)
Thus;
x = molar solubility
= √ (5.1 x 10^-9)
= 7.1 x 10^-5 M
Therefore;
Mass BaCO3 = 7.1 x 10^-5 M x 1 L x 197.34 g/mol
= 0.014 g
Answer:
Explanation:
In the chlorination of alkanes, the condition necessary is UV light so free radical substitution can take place. For alkanes like pentane, the primary, secondary and tertiary Hydrogen atoms (Hydrogen atoms bonded to their respective carbon) þare taken into consideration and this is because the tertiary Hydrogen is the most reactive (due to bond dissociation energy) hence the easiest to be substituted. The trend is as follows in the order of their reactivity;
1° < 2° < 3°
So, the products of the chlorination of pentane, the principal monochloride constituted is 3 - chloropentane while the other two monomers are:
2- chloropentane
1- chloropentane
Below is the attachment showing the structural formula of the three monochloride constituted pentane.
Answer:
The correct answer is 0.09 percent.
Explanation:
Based on the given information, the atomic radius is 2 × 10⁻¹⁰ m. Now the atomic volume can be determined by using the formula, 4/3πr³. by putting the values we get,
v = 4/3πr³ = 4/3π(2×10⁻¹⁰ m)³
v = 3.35 × 10⁻²⁹ m³
The no. of atoms present in one mole of xenon is 6.02 × 10²³ atoms. Therefore, the total atomic volume will be,
Va = 6.02 × 10²³ × 3.35 × 10⁻²⁹
Va = 2.02 × 10⁻⁵ m³
The %age of total volume occupied can be determined by dividing the total atomic volume with the volume under STP. Under STP, the volume is 22.4 m³ or 2.24 × 10⁻² m³.
Va/V = 2.02 × 10⁻⁵ m³ / 2.24 × 10⁻² m³
= 9.02 × 10⁻⁴ or 0.09 %
Your correct! Radio waves I’m pretty sure!
