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bogdanovich [222]
4 years ago
12

What is the percent composition of a solution in which 480 grams of sodium chloride, NaCl, is dissolved in 4 liters of solution.

Chemistry
1 answer:
ZanzabumX [31]4 years ago
8 0
 12% NaCl is the answer I came to... Have a GREAT day!!! :)

You might be interested in
A compound contains 24.27% C, 4.07% H and 71.65% Cl. The molar mass is about 99g.
Schach [20]

Answer:

Molecular formula = C₂H₄Cl₂

Explanation:

Molecular formula:

Molecular formula consist of symbols of elements present in compound with numbers of atoms of each element in subscript.

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number .

Given data:

Percentage of hydrogen = 4.07%

Percentage of Cl = 71.65%

Percentage of carbon = 24.27%

Molar mass = 99 g/mol

Molecular formula = ?

Solution:

Number of gram atoms of H = 4.07 / 1.01 = 4.0

Number of gram atoms of Cl = 71.65 / 35.5 = 2.0

Number of gram atoms of C = 24.27 / 12 = 2.0

Atomic ratio:

           H              :          C             :         Cl

          4/2            :        2/2            :       2/2

           2               :          1             :        1

C : H : Cl = 1 : 2 : 1

Empirical formula is CH₂Cl.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 12+1×2+ 35.5 = 49.5

n =  99/49.5

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 ( CH₂Cl)

Molecular formula = C₂H₄Cl₂

5 0
3 years ago
When zn(oh)2(s) was added to 1.00 l of a basic solution, 1.09×10−2 mol of the solid dissolved. what is the concentration of oh−
uysha [10]
The concentration of the basic solution is determined by:

N = (number of moles / volume of solution) 

number of moles = 1.09 x 10^-2 mol
volume of solution = 1 liter
N of basic solution = 1.09 x 10^-2 mol / 1 liter
N = 1.09 x 10^-2 mol/L

The initial concentration of Zn (OH)2 is 0; the basic solution is 1.09x10^-2 M, then the concentration of OH in the final solution is 1.09x10^-2 M



7 0
3 years ago
Read 2 more answers
Girls are usually completely physically mature by _____ years old.
krok68 [10]

Answer:

a 17 bc it is how it works

5 0
3 years ago
Read 2 more answers
2.
gregori [183]

Answer:

160

Explanation:

p*v/t = constant

or

p1*v1/t1 = p2*v2/t2

pressure is not stated in question so we get rid of it on both sides

v1/t1 = v2/t2

we are finding temperature so we flip the entire equation

t1/v1 = t2/v2

200/5 = t2/4

4(200/5) = t2

=160

7 0
3 years ago
Read 2 more answers
Na2CO3 + 2HCl ---------> 2NaCl + CO2 + H2O How many moles of NaCl are produced from the reaction of 1.67 x 1022 molecules of
dexar [7]

Answer:

0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.

Explanation:

The balanced reaction is:

Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • HCl: 2 moles
  • NaCl: 2 moles
  • CO₂: 1 mole
  • H₂O: 1 mole

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles=\frac{1.67*10^{22}molecules*1mole }{6.023*10^{23}molecules}

amount of moles= 0.0277 moles

In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl=\frac{0.0277 moles of Na_{2} CO_{3}*2 moles of NaCl }{1 mole of Na_{2} CO_{3}}

amount of moles of NaCl= 0.0554 moles

<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>

8 0
3 years ago
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