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shutvik [7]
3 years ago
8

A 50kg crate is being pushed on a horizontal floor at a constant velocity. The coefficient of kinetic friction between the crate

and the floor is 0.1. How much force is applied to the crate?
Physics
1 answer:
Inessa [10]3 years ago
5 0
Ч= 0.1
m= 50kg

F_{f} =чmg
= (0.1)(50)
= 5 N

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Answer:

\boxed {\boxed {\sf 6 \ meters}}

Explanation:

Work is the product of force and distance.

W=F*d

We know that 96 Joules of work were done and a 16 Newton force was applied to the object.

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Substitute the values into the formula.

96 \  J= 16 \ N * d

First, let's convert the units. This will make cancelling units easier later in the problem. 1 Joule (J) is equal to 1 Newton meter (N*m), so the work of 96 Joules equals 96 Newton meters.

96 \ N*m= 16 \ N * d

Now, solve for distance by isolating the variable, d. It is being multiplied by 16 Newtons and the inverse of multiplication is division. Divide both sides of the equation by 16 N.

\frac {96 \ N*m}{16 \ N}= \frac{16 \ N *d}{16 \ N}

\frac {96 \ N*m}{16 \ N}=d

The units of Newtons cancel.

\frac {96}{16} \ m = d

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zhannawk [14.2K]

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0.947-0.3831= 0.5639m

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