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Marysya12 [62]
3 years ago
10

What is the point of doing an experiment. Help thank you​

Chemistry
2 answers:
bogdanovich [222]3 years ago
7 0

Answer:

to find out how somethings work

Explanation:

Softa [21]3 years ago
4 0

Answer:

Doing experiments is good because when you try these possibilities you can learn about something that you've tried or see why this experiment didn't really work. It also helps you understand that  not everything you try will work. that's why we experiment.

Explanation:

Hope this helps:)

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The photograph shows one of the boats in a science club's toy boat race. All the boats were powered by identical
____ [38]

Answer:

Boat p

Explanation:

4 0
3 years ago
Read 2 more answers
PLEASE ANSWER FAST AND YOU WILL GET BRAINLIESTTTTTTT!!!!!!! And POINTSSSSSS!! PLEASE ANSWER FAST AND YOU WILL GET points and BRA
stiks02 [169]

Answer:

B on both questions

Explanation:

6 0
2 years ago
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I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
2 years ago
Silicon has 2 isotopes, Silicon-28 with an abundance of 90% and Silicon-30 with an abundance of 10%. Find the AAM for Silicon.
JulsSmile [24]

Answer:

RAM

RAM = (mass \: of \:  ^{28} Si \:  \times \%abundance) + (mass \: of \:  ^{30} Si \:  \times \%abundance) \\ RAM = (28 \times 90\%) + (30 \times 10\%) \\ RAM = 25.2 + 3 \\ RAM = 28.2

5 0
2 years ago
Pls Help!!!!! ASAP!!!!​
HACTEHA [7]

Answer:

do u need help mentally?

Explanation:

:>

7 0
2 years ago
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