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lakkis [162]
3 years ago
11

A model rocket accelerates upward from the ground with a constant acceleration, reaching a height of 50 m in 8 s.What is the spe

ed (in m/s) at a height of 50 m?A: 1.07×101 B: 1.25×101 C: 1.46×101 D: 1.71×101 E: 2.00×101
Physics
1 answer:
LekaFEV [45]3 years ago
5 0

Answer:

The  value is  v =  12.5 \  m/s

Explanation:

From the question we are told that

    The  height is  h  =  50 \  m

    The  time taken is  t =  8 \ s

   

From the equation of motion we have  that

 s =  ut + \frac{1}{2}  * a * t^2

Here u = 0  because the rocket started at rest

  50 =  0 + \frac{1}{2} * a  * 8^2

=>   a =  \frac{100}{64}

=>    a =  1.5625 \ m/s^2

Also from the kinematic equation we have that

    v  =  u + at

=>  v =  0 +  (8  *  1.5625)

=>   v =  12.5 \  m/s

       

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