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SashulF [63]
3 years ago
9

Kyle travelled a total of 762 miles during his vacations to the United States. How many kilometers did he travel?

Chemistry
1 answer:
Mashutka [201]3 years ago
4 0
762 miles = 1226.32 kilometers
you multiply the miles by 1.609 to get the kilometers
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The movement of electrons causes:
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Your answer is B ;) the movement of electrons cause electrical energy :)


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3 years ago
The first-order isomerization reaction: cyclopropane → propene has a rate constant of 1.10×10-4 s-1 at 470°C and 5.70×10-4 s-1 a
BigorU [14]

Answer:

Activation energy, Ea, for the reaction 261.7 kj/mole

Explanation:

Given

Rate constant at 470 ⁰C (K₁) = 1.10 x 10⁻⁴ s⁻¹ and rate constant at 500⁰C (K₂) = 5.7 x 10⁻⁴ s⁻¹

Temperature (T₁) = 470 + 273 = 743 K and

temperature (T₂) = 500 + 273 = 773 K

Activation energy (Eₐ) = ?

Universal gas constant (R) = 8.314 J. K⁻¹. mole⁻¹

We know   log\frac{K_{2} }{K_{1} } = \frac{E_{a} }{2.303XR}\frac{(T_{2}-T_{1} ) }{T_{2}T_{1}  }

              ⇒ log \frac{5.7 X 10^{-4} }{1.1 X 10^{-4} } = \frac{E_{a} }{2.303X8.314} \frac{(773 - 743)}{773X743}

              ⇒ 0.714 = \frac{E_{a}X30 }{10996950.3}

              ⇒ Eₐ = \frac{7851822.5}{30} j/mole = 261.7 Kj/mole

5 0
3 years ago
Why is the separation of mixtures into pure or relatively pure substances so important when performing a chemical analysis?
N76 [4]

Answer:

It is important to separate mixture into pure or relatively pure substances when performing a chemical analysis SO AS TO KNOW THE PROPERTIES COMING FROM EACH PART MIXTURE WHICH MAY INTERFERE WITH THE SEPARATION.

Explanation:

In chemistry, Mixture is the combination of two or more substances which are not combine chemically.

Mixture contain different substances with different physical and chemical properties.

It is important to purify the substances in a mixture so as to identify what properties are coming from each mixture and also some part of the mixture can interfere with the properties of other mixture present for skewing analysis.

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Answer numbers 1-8<br> (Don't answer if you don't know)
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What molarity should the stock solution be if you ant to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103M? a.
nadya68 [22]
A common dilution relationship is (M1V1)=(M2V2)
(0.103M x 2.00L) = (M2 x 0.025L)
M2= <span>(0.103M x 2.00L)/0.025L
M2= 8.24M</span>
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3 years ago
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