I think it is b..................................................
Answer:
1.18 × 10²⁴ particles Mg
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
47.7 g Mg
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Mg - 24.31 g/mol
<u>Step 3: Convert</u>
<u />
= 1.18161 × 10²⁴ particles Mg
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg
The amount (in pounds) the gasoline tank will hold when full is 153.76 lb
<h3>What is density? </h3>
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
<h3>How to convert gallon to milliliters </h3>
1 gallon = 3785.412 mL
Therefore,
25 gallon = 25 × 3785.412
25 gallon = 94635.3 mL
<h3>How to determine the mass </h3>
- Density = 0.737 g/mL
- Volume = 94635.3 mL
- Mass =?
Mass = Density × Volume
Mass = 0.737 × 94635.3
Mass = 69746.2161 g
<h3>How to convert grams to pounds </h3>
453.592 g = 1 lb
Therefore,
69746.2161 g = 69746.2161 / 453.592
69746.2161 g = 153.76 lb
Learn more about density:
brainly.com/question/952755
#SPJ1
To reduce a haloalkane, it has to be eliminated first. This is because 2 bromopropanes are a saturated compound that can not be reduced by a saturated compound. Dehydrohalogenation of the haloalkanes into the form of propene and hydrogen bromide can lead to the elimination. The propene is then reduced to propane.
