If 0.580 moles of a monoprotic weak acid (ka = 7.4 10-5 is titrated with naoh, what is the ph of the solution at the half-equiva
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Answer:
3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.
Explanation:
Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
= Initial temperature of the substance
= Final temperature of the substance
We have mass of isopropyl alcohol = m = 25.0 g
Specific heat of isopropyl alcohol = c = 2.604 J/g°C
Initial temperature of the isopropyl alcohol =
Final temperature of the isopropyl alcohol =
Heat absorbed by the isopropyl alcohol to boil:
3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.