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3 years ago

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Chemistry

2 answers:

Papessa [141]3 years ago

7 0

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olya-2409 [2.1K]3 years ago

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And the help is.....?!

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why mixture of stone pebbles And water is concerned considered suspension you are provided with a mixture of sand salt and camph

baherus [9]

Answer:

camphor sublimates salt is soluble in water while sand does not sublime and does not dissolve in water you first heat the mixture in a beaker covered with a watch glass camphor will then accumulate on the watch glass then you dissolve the remaining mixture of sand and salt salt will dissolve forming a salt solution then you filter using a filter paper and a beaker the residue on the filter paper is sand while the filtrate is salt solution you then heat the salt solution so that it can evaporate leaving salt particles thus you will have obtained salt sand and camphor

6 0

3 years ago

I need to check some chemistry questions. Help with any question is appreciated! :) Please include an explanation with your conc

finlep [7]

1. 4.67 kg; 2. 4.8 ×10^5 kg; 3. 0.106 cm^3; 4. 1.7 g/cm^3

Q1. Mass of Hg

Mass = 345 mL × (13.53 g/1 mL) = 4670 g = 4.67 kg

Q2. Mass of Pb

Step 1. Calculate the volume of the Pb.

V = lwh = 6.0 m × 3.5 m × 2.0 m = 42.0 m^3

Step 2. Calculate the mass of the Pb.

Mass = 42.0 m^3 × (11 340 kg/1 m^3) = 4.8 × 10^5 kg

Q3. Volume of displaced water

Volume of Ag = 0.987 g × (1 cm^3/9.320 g) = 0.106 cm^3

Archimedes: volume of displaced water = volume of Ag = 0.106 cm^3

4. Density of metal

Step 1. Convert ounces to grams

Mass = 3.35 oz × (28.35 g/1 oz) = 94.97 g

Step 2. Calculate the volume in cubic inches

V = lwh = 3.0 in × 2.5 in × 0.45 in = 3.38 in^3

Step 3. Convert cubic inches to cubic centimetres

V = 3.38 in^3 × (2.54 cm/1 in)^3 = 55.3 cm^3

Step 4. Calculate the density

ρ = m/V = (94.97 g/55.3 cm^3) = 1.7 g/cm^3 (magnesium?)

4 0

3 years ago

Calculate the molar solubility of fe(oh)2 in pure water. (the value of ksp for fe(oh)2 is 4.87×10−17.)

rosijanka [135]

When we have this balanced equation for a reaction:
Fe(OH)2(s) ↔ Fe+2 + 2OH-

when Fe(OH)2 give 1 mole of Fe+2 & 2 mol of OH-
so we can assume [Fe+2] = X and [OH-] = 2 X
when Ksp = [Fe+2][OH-]^2
and have Ksp = 4.87x10^-17
[Fe+2]= X
[OH-] = 2X
so by substitution
4.87x10^-17 = X*(2X)^2
∴X^3 = 4.8x10^-17 / 4
∴the molar solubility X = 2.3x10^-6 M

3 0

3 years ago

Is a particle with a positive charge.:)

tatyana61 [14]

Proton is the answer

8 0

3 years ago

How many moles of ions would you expect in an aqueous solution containing one mole of chromium(III) chloride? Hint: write out th

Cerrena [4.2K]

Answer:

Four

Explanation:

AlCl₃(aq) ⟶ Al³⁺(aq) + 3Cl⁻(aq)

One mole of AlCl₃ produces 1 mol of Al³⁺ and 3 mol of Cl⁻.

That's four moles of ions.

8 0

2 years ago