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yKpoI14uk [10]
3 years ago
7

Wisdom teeth are the third and final set of human molars that come in during the late teens or early twenties. In some cases, th

ese teeth come in without problems, but they often have to be removed due to misalignment in the jaw, as shown below. Removal of the teeth does not cause any long-term complications in regard to eating. mc012-1.jpg Which type of anatomic structure are wisdom teeth?
Chemistry
2 answers:
sdas [7]3 years ago
6 0
A. Vestigial is the correct answer
Marina86 [1]3 years ago
5 0
The answer is Vestigal.  It is a type of anatomical structure that no longer serves any function. Over time they are no longer needed in the body.  Apart from the wisdom tooth, another example would be the tail bone which has no use for humans.
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A covalent bond forms a(n) ______________.
DiKsa [7]
The answer is Molecule. After a pair of shared electrons orbit around the nuclei of both atoms
3 0
2 years ago
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The density of a metal cube is 8 x103 kg/m3. Convert
Rom4ik [11]

Answer:

Explanation:

[peirod4

4 0
3 years ago
A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o
statuscvo [17]

Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = 61.1^{0}C

Heat absorbed by Scandium = 1.50*10^{3}J

The equation showing the relationship between heat, mass, specific heat and temperature change:

Q = m C (deltaT)

Where Q is heat = 1.50*10^{3}J

m is mass = 50.0 g

ΔT = 61.1^{0}C

On plugging in the values and solving for C(specific heat) we get,

1.50*10^{3}J=50.0g(C)(61.1^{0}C)

C = 0.491\frac{J}{g^{0}C }

Specific heat of the metal = 0.491\frac{J}{g^{0}C }

7 0
3 years ago
How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?
Nina [5.8K]

11.48-gram of KCl0_3 are needed to produce 6.75 Liters of O_2  gas measured at 1.3 atm pressure and 298 K

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=298 K

Putting value in the given equation:

\frac{PV}{RT}=n

n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}

Moles = 0.3588 moles

Now,

Moles = \frac{mass}{molar \;mass}

0.3588 moles = \frac{mass}{32}

Mass= 11.48 gram

Hence, 11.48-gram of KCl0_3 are needed to produce 6.75 Liters of O_2 gas measured at 1.3 atm pressure and 298 K

Learn more about the ideal gas here:

brainly.com/question/27691721

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3 0
2 years ago
When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation of two new nuc
user100 [1]

Answer:

^{139}_{56}Ba

Explanation:

The fission reaction taking place given in the question is:

^{235}_{92}U+^{1}_{0}n\rightarrow ^{A}_{Z}Ba+^{94}_{36}Kr+3^{1}_{0}n

The mass is conserved in the reaction.

So,

235 + 1 = A + 94 + 3×1

A = 139 g/mol

Also, number o protons remain same. So,

92  = Z + 36

Z = 56

The isotopic symbol is ^{139}_{56}Ba

5 0
3 years ago
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