<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%7D" id="TexFormula1" title="\sqrt[3]{4}" alt="\sqrt[3]{4}" align="absmiddle

X/3=-3 can someone help me

laiz [17]

Answer:

x = - 9

Step-by-step explanation:

Given

$\frac{x}{3}$ = - 3 ( multiply both sides by 3 to clear the fraction )

x = - 9

7 0

3 years ago

Determine whether the random variable is discrete or continuous. a. The number of statistics students now reading a book. b. The

andrey2020 [161]

Answer:

Continuous random variables: c and e

Discrete random variables: a, b, d

Step-by-step explanation:

We have to identify whether the random variable is discrete or continuous.

A discrete variable is a variable whose value is obtained by counting.
A continuous random variable X takes all values in a given interval of numbers.
Thus, a continuous variable can have values in decimals but a discrete random variable cannot take values in decimals.

a. The number of statistics students now reading a book.

Discrete random variable since number of students cannot take decimal values.

b. The number of textbook authors now sitting at a computer.

Discrete random variable since number of textbooks cannot be expressed in decimals but counted.

c. The exact time it takes to evaluate 27 plus 72.

It is a continuous random variable as it may take all values within an interval of time.

d. The number of free dash throw attempts before the first shot is made.

It is a discrete random variable since the number of throws can always be whole number.

e. The time it takes to fly from City Upper A to City Upper B.

Time is a continuous random variable.

6 0

3 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$