Answer:
30 mL VOLUME OF 3.0 M HCl SHOULD BE USED BY THE STUDENT TO MAKE A 1.80 M IN 50 mL OF HCl.
Explanation:
M1 = 3.00 M
M2 = 1.80 M
V2 = 50 .0 mL = 50 /1000 L = 0.05 L
V1 = unknown
In solving this question, we know that number of moles of a solution is equal to the molar concentration multiplied by the volume. To compare two samples, we equate both number of moles and substitute for the required component.
So we use the equation:
M1 V1 = M2 V2
V1 = M2 V2 / M1
V2 = 1.80 * 0.05 / 3.0
V2 = 0.09 /3.0
V2 = 0.03 L or 30 mL
To prepare the sample of 1.80 M HCl in 50.0 mL from a 3.0 M HCl, 30 mL volume should be used.
Answer:
Not balance.
Explanation:
Chemical equation:
K + Cl₂ → KCl
The given equation is not balance because there are one potassium and two chlorine atoms on left side of equation while on right side there are one potassium and one chlorine atom present.
Balance chemical equation:
2K + Cl₂ → 2KCl
the equation is balance now because there are two potassium and two chlorine atoms on left side of equation and two potassium and two chlorine atoms are also present on right side.
Answer:
are easily broken
Explanation:
The double covalent bond within unsaturated hydrocarbons are easily broken.
Given the data from the question, the identity of the unknown metal having a of mass 133 g is Cobalt
<h3>What is density? </h3>
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
<h3>How to determine the density </h3>
- Mass = 133 g
- Volume of water = 25 mL
- Volume of water + metal = 40 mL
- Vol of metal = 40 – 25 = 15 mL
Density = mass / volume
Density = 133 / 15
Density = 8.86 g/mL
Comparing the density of the unknown metal (i.e 8.86 g/mL) with those given in the chart in the question above, we can conclude that the unknown metal is Cobalt
Learn more about density:
brainly.com/question/952755
