Let
C---------> the circumference of a circle
D---------> diameter of a circle
r----------> radius of a circle
we know that
C=2*pi*r
D=2*r
so
C=D*pi-------------> pi=C/D
<span>Pi is defined as the ratio of the circumference of a circle to the diameter of that Circle
when you multiply the diameter in both numerator and denominator
pi*D=(C/D)*D------> pi*D=C
and the diameter is two times the radius
so
D=2*r
C=pi*D------> C=pi*(2*r)-----> C=2*pi*r
therefore
the answer is the option D
</span>Two times r equals the diameter of the circle. Pi equals the circumference divided by the diameter. When you multiply, the diameter is in both the numerator and the denominator, which cancels out, leaving the circumference
Answer:
do you have what x and/or y equals
Step-by-step explanation:
Answer:
(a) 0.2721
(b) 0.7279
(c) 0.2415
Step-by-step explanation:
(a) If we choose only one student, the probability of being a math major is 
(because there are 5 math majors in a class of 18 students). So, the probability of not being a math major is 
(we subtract the math majors of the total of students).
But there are 4 students in the group and we need them all to be not math majors. The probability for each one of not being a math major is 
and we have to multiply them because it happens all at the same time.
P (no math majors in the group) = 
= 0.2721
(b) If the group has at least one math major, it has one, two, three or four. That's the complement (exactly the opposite) of having no math majors in the group. That means 1 = P (at least one math major) + P (no math major). We calculated this last probability in (a).
So, P (at least one math major) = 1 - P(no math major) = 1 - 0.2721 = 0.7279
(c) In the group of 4, we need exactly 2 math majors and 2 not math majors. As we saw in (a), the probability of having a math major in the group is 5/18 and having a not math major is . We need two of both, that's 
. But we also need to multiply this by the combinations of getting 2 of 4, that is given by the binomial coefficient 
.
So, P (exactly 2 math majors) = 
= 
= 0.2415
Answer:
#3=51. #5=85
Step-by-step explanation:
#3. PEMDAS
(2-10×6)-7
PARENTHESIS FIRST
MULTIPLICATION FIRST
10×6=60
60-2=58
58-7=51
#5. PEMDAS
(12-11)+12×7
PARENTHESIS FIRST
12-11=1
1+12×7
MULTIPLICATION FIRST
12×7=84
84+1=85
This is question of geometric sequence, equation of growth for this matter. The explicit formula for geometric sequence is given by:
a(n) = a(0)r^(n-1)
where;
a(n) = population after time "n"
a(0) = Initial population = 65
n = time = 5 weeks
r = common ratio = (100+30)% = 1.3
Substituting, beetles after 5 weeks will be;
a(5) = 65*1.3^(5-1) = 185.65 ≈ 186 beetles
