Cathode rays were shown to be a stream of "electrons".
Cathode rays (likewise called an electron beam) are streams of electrons saw in vacuum tubes. In the event that a cleared glass tube is outfitted with two anodes and a voltage is connected, the glass inverse the negative terminal is seen to sparkle from electrons radiated from the cathode. Electrons were first found as the constituents of cathode beams. The picture in an exemplary TV is made by centered light emission redirected by electric or magnetic fields in cathode ray tubes (CRTs).
Answer:
V₁ = 5.6 m/s
V₂ = 7.2 m/s
V₃ = 8.8 m/s
Explanation:
Average velocity: Average velocity can be defined as the ratio of the total displacement to the total time taken. The S.I unit of Average velocity is m/s.
For the first 2 s,
V₁ = Δd₁/t
Where V₁ = Average velocity for the first 2 s
Where Δd₁= distance, t = time
Δd₁ = 25.6-14.4 = 11.2 m t = 2 s
V₁ = 11.2/2
V₁ = 5.6 m/s
For the second 2 s,
V₂ =Δd₂/t
Where V₂ = average velocity for the second 2 s.
Δd₂= 40-25.6 = 14.4 m, t= 2 s
V₂ = 14.4/2
V₂ = 7.2 m/s
For the last 2 seconds,
V₃ =Δd₃/t
Where V₃ = average velocity for the last 2 s
where Δd₃ = 57.6- 40 = 17.6 m, t = 2 s
V₃ = 17.6/2
V₃ = 8.8 m/s.
Answer:
um it well it will be 19.6 d) 9.8 J
Explanation:
The escape velocity on Venus is 9761 m/s
Explanation:
The escape velocity from a planet is the speed that an object on the surface of that planet must have in order to completely escape the gravitational field of the planet.
Mathematically, it is calculated as
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
For Venus, we have:
is the mass
is the radius
Substituting, we find the escape velocity on Venus:
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The answer would be . Since we are looking for the spring constant you would need to use the formula
. Then you'd substitute, for PEs and x.
Then solve. k=500n/m
