Answer:
8.67×10⁻⁶ N/m²
Explanation:
p = Momentum of a photon
E = Energy of a photon
c = Speed of light
I = Intensity of light
Force = dp/dt


As given in question

Now F/A = Pressure

∴ Magnitude of the pressure on the sail is 8.67×10⁻⁶ N/m²
Answer:

Explanation:
Given,
Width of slit, W = 5.7 x 10⁻⁴ m
Distance between central bright fringe, L = 4 m
distance between central bright fringe and first dark fringe, y = 4 mm
Diffraction angle



Now.

m = 1



The source of energy that keeps the Sun shining today is _________.
<u>Is nuclear fusion</u>
~Hope this answers your question!~
1. Each plot represents the meters traveled by both the Hare and the Tortoise over a certain period of time (minutes).
2. The Tortoise lines show it lines is steadily increasing over a period of time. So as more time elapses the faster the tortoise becomes it travels more meters. The Tortoise line shows steady acceleration.
3. The Hare in the first 5 minutes had a rapid fast advancement up to 40 meters. But for the 5-20 mins. period the Hare did not move at all. Its speed stayed at the same place. But towards the end 20-25 mins. marks the Hare started moving again. At the end the Hare at first had a rapid acceleration but stopped for a long time then it sped up briefly.
Answer:
The activation energy is
Explanation:
From the question we are told that
The rate constant is k
at the temperature 
The value of k is 
at temperature 
The value of k is 
The rate constant is mathematically represented as

Where Q is the activation energy
R is the ideal gas constant with a value of 
C is a constant
T is the temperature
For the first rate constant

For the second rate constant

Now the ratio between the two given rate constant is
![\frac{k_1 }{k_2} = e^{(\frac{Q}{R} [\frac{1}{\frac{T_2 - 1}{T_1} } ] )}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_1%20%7D%7Bk_2%7D%20%20%3D%20%20e%5E%7B%28%5Cfrac%7BQ%7D%7BR%7D%20%5B%5Cfrac%7B1%7D%7B%5Cfrac%7BT_2%20-%201%7D%7BT_1%7D%20%7D%20%5D%20%29%7D)
=> ![ln [\frac{k_1}{k_2} ] = \frac{Q}{R} * [\frac{1}{\frac{T_2 -1}{T_1} } ]](https://tex.z-dn.net/?f=ln%20%5B%5Cfrac%7Bk_1%7D%7Bk_2%7D%20%5D%20%3D%20%20%5Cfrac%7BQ%7D%7BR%7D%20%20%2A%20%5B%5Cfrac%7B1%7D%7B%5Cfrac%7BT_2%20-1%7D%7BT_1%7D%20%7D%20%5D)
substituting values
![ln [\frac{1.05 *10^{-8}}{2.95 *10^{-4}} ] = \frac{Q}{8.314} * [\frac{1}{\frac{673 -1}{573} } ]](https://tex.z-dn.net/?f=ln%20%5B%5Cfrac%7B1.05%20%2A10%5E%7B-8%7D%7D%7B2.95%20%2A10%5E%7B-4%7D%7D%20%5D%20%3D%20%20%5Cfrac%7BQ%7D%7B8.314%7D%20%20%2A%20%5B%5Cfrac%7B1%7D%7B%5Cfrac%7B673%20-1%7D%7B573%7D%20%7D%20%5D)
=> 