Answer:
the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.
Explanation:
Given:
f₁ = frequency = 266 Hz
f₂ = 400 Hz
Question: How do the wavelength of each of these sound waves compare, λ₁ = ?, λ₂ = ?
The equation to solve this question is
Here
λ = wavelength of the sound
v = speed of sound = 340 m/s
f = frequency of each instrument
You need to calculate both wavelengths
According to the results, the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.