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ivolga24 [154]
3 years ago
11

Describe the relationship between the distance of fall and diameter of the parent drop

Chemistry
1 answer:
rodikova [14]3 years ago
7 0
I am not sure if you have any questions or need any further information please login to your mom do you have any questions or need
You might be interested in
If input energyis 100J and useful is 70J what is the waste energy
Oliga [24]

Answer:

waste energy = 30 J

Explanation:

Given that.

Input energy = 100 J

Useful energy = 70 J

We need to find the amount of waste energy.

Waste energy = total energy - used energy

= 100 J - 70 J

= 30 J

Hence, 30 J of energy is waste energy.

4 0
3 years ago
Potassium Oxide + Calcium Chlorate react to form what (double replacement)
Dennis_Churaev [7]
They would react to form:

Potassium Chlorate + Calcium Oxide

Here is an attachment with the skeleton equation and balance:


3 0
3 years ago
Which step do you use first to calculate the number of grams of FeCl2 produced when
Zielflug [23.3K]
30.987 is 4576vhnj
Jjjk
5 0
3 years ago
How many moles of oxygen atom are there in 0.5 moles of Ca(ClO3) 2?
FinnZ [79.3K]

Answer:

Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Explanation:

(jayaanilanmol's answer)

3 0
3 years ago
10. What is the specific heat of an unknown substance if a 2.50 g sample releases 12 calories as its
Sergeu [11.5K]

Answer:

c = 4016.64 j/g.°C

Explanation:

Given data:

Mass of substance = 2.50 g

Calories release = 12 cal (12 ×4184 = 50208 j)

Initial temperature = 25°C

Final temperature = 20°C

Specific heat of substance = ?

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Solution:

Q = m.c. ΔT

ΔT  = T2 - T1

ΔT  = 20°C - 25°C

ΔT  = -5°C

50208 j = 2.50 g . c. -5°C

50208 j = -12.5 g.°C .c

50208 j /-12.5 g.°C =  c

c = 4016.64 j/g.°C

4 0
3 years ago
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