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3 years ago

Describe the relationship between the distance of fall and diameter of the parent drop

1 answer:

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Identify the change in state that does NOT have an increase in entropy. Identify the change in state that does NOT have an incre

Lena [83]

Answer:

condensing water

Explanation:

Entropy refers to the level of disorderliness in a system. The entropy of liquids is greater than that of solids. The entropy of gases is greater than that of liquids.

A process of physical change involving a change of state from solid to liquid or liquid to gas is accompanied by increase in entropy.

However, a change of state involving a change from liquid to solid or gas to liquid is accompanied by decrease in entropy.

Hence, steam condensing to water leads to decrease and not increase in entropy of the system.

4 0

3 years ago

Which type of basin forms at transform boundaries? rift wedge arc strike-slip

Blababa [14]

Answer:

Strike slip forms at transform boundaries

4 0

3 years ago

Read 2 more answers

2. Calculate the [H+] in the following solutions, given their pH, and identify the solution as acidic, basic or neutral.

givi [52]

Answer:

a) acidic; [H+] = 10^-2.5 = 3 x 10^-3

b) basic; [H+] = 10^-11.7 = 2 x 10^-12

c) slightly acidic (almost neutral); [H+] = 10^-6.8 = 1.6 x 10^-7

d) acidic; [H+] = 10^-3.31 = 4.9 x 10^-4

Explanation:

pH < 7 is acidic; pH > 7 is basic; pH = 7 is neutral

[H+] = 10^-pH

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3 years ago

Calculate the percentage of the void space out of the total volume occupied by 1 mole of water molecules. The density of water i

gtnhenbr [62]

Answer:

The percentage of the void space out of the total volume occupied is 93.11%

Explanation:

A mole of water contains 2 atoms of hydrogen and 1 atom of oxygen.

To calculate the volume of a mole of water, we calculate 2 times the volume of the hydrogen atom and 1 times the volume of the oxygen atom

Let's calculate this one after the other.

For the hydrogen, formula for the volume will be

$V_{hydrogen$ = 2 × 4/3 × π × $r_{H}^{3}$

where $r_{H}^{3}$ = 37 pm which is read as 37 picometer (1 picometer = 10^-12 m) = 37 × $10^{-12}$ meters

Volume of the hydrogen = 8/3 × (37 × 10^-12)^3 = 4.05 * 10^-31

we multiply this by the avogadro's number = 6.02 * 10^23

= 4.05 * 10^-31 * 6.02 * 10^23 = 2.6 * 10^-8 m^3

We do same for thr oxygen, but this time we do not multiply the volume of the oxygen by 2 as we have only one atom of oxygen

Volume of oxygen = 4/3 * π * (73 * 10^-12) ^3 * avogadro's number = 9.81 * 10^-7 m^3

adding both volumes together, we have 1.24 * 10^-6 m^3 or simply 1.24 ml ( 0.01 m = 1 ml)

Dividing the molar mass of one mole of water by its density, we can get the volume of 1 mole of water

= (18g/mol)/(1 g/ml) = 18 ml/mol

Now we proceed to calculate the volume of void = Total volume - volume of molecule = 18 - 1.24 = 16.76 ml

Now, the percentage of void = volume of void/total volume * 100%

= 16.76/18 * 100% = 93.11%

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3 years ago

A solution of permanganate is standardized by titration with oxalic acid, . To react completely with mol of oxalic acid required

Zielflug [23.3K]

Answer:

$M=0.120M$

Explanation:

Hello,

In this case, the undergone chemical reaction is:

$MnO_4^-(aq)+H_2C_2O_4(aq)\rightarrow Mn^{+2}+CO_2$

In such a way, the acidic redox balance turns out:

$(Mn^{+7}O_4)^-+5e^-+8H^+\rightarrow Mn^{+2}+4H_2O\\H_2C_2O_4\rightarrow2CO_2+2H^++2e^-$

Which leads to the total balanced equation as follows:

$2(MnO_4)^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow2Mn^{+2}(aq)+8H_2O(l)+10CO_2(g)$

Thus, as the mass of oxalic acid is not given, one could suppose a value of 1 g (which you can modify based on the actual statement) in order to compute the oxalic acid moles as shwon below:

$1gH_2C_2O_4*\frac{1molH_2C_2O_4}{90.04gH_2C_2O_4} *\frac{2mol(MnO_4)^-}{5molH_2C_2O_4} =0.00444mol(MnO_4)^-$

Whereby the molality results:

$M=\frac{0.00444mol(MnO_4)^-}{0.03702L} =0.120M$

Remember you can modify the oxalic acid mass as you desire.

Best regards.

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4 years ago