Answer:
violet
Explanation:
Waves with a short wavelength have the most energy. Red waves have a relatively long wavelength (in the 700 nm range), and violet waves are much shorter - roughly half that. Because violet waves have the shortest wavelength of the visible light spectrum, they carry the most energy (google)
Answer:
m H2(g) = 2.241 g H2(g)
Explanation:
- 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)
limit reagent:
∴ Mw Al = 26.982 g/mol
∴ Mw H2SO4 = 98.0785 g/mol
⇒ n Al = (20 g Al)×(mol/26.982 g) = 0.7412 mol Al
⇒ n H2SO4 = ( 115 g H2SO4 )×(mol/98.0785 g) = 1.173 mol H2SO4
⇒ n H2 = (0.7412 mol Al)×(3 mol H2/ 2 mol Al) = 1.112 mol H2
∴ Mw H2 = 2.016 g/mol
⇒ g H2 = (1.112 mol H2)×(2.016 g/mol) = 2.241 g H2
Answer:
a. AlCl is incorrect because Al has a +3 charge while Cl only has a -1 charge. The correct formula would be AlCl₃. This balances the charges.
b. Na₃SO₄ is incorrect because Na has a charge of +1 and there are three of them so its +3 and SO₄ has a charge of -2. The correct formula would be Na₂SO₄. This balances the charges.
c. BaOH₂ is incorrect because the polyatomic ion OH would not be written that way. It would be written like this Ba(OH)₂. Writing it like BaOH₂ gives the impression that instead of having 2 OH it has 2 H and 1 O.
d. Fe₂O is incorrect because Fe either has a +2 charge or +3 charge while O has a -2 charge. Possible correct answers could be FeO (iron (II) oxide) or Fe₂O₃ (iron (III) oxide).
Mass × velocity = momentum
74 x 15 = momentum
Quantum numbers are used to describe the location of electrons in atoms.
Principal quantum number(n) tells which energy shell the electrons reside in.
The first energy shell n = 1, second energy shell n = 2 and it goes on.
Azimuthal quantum number (l) states which orbital the electron is most likely to reside in. the number of orbitals in an energy shell depends on the principal quantum number. number of orbitals are from 0 to n-1
If l = 0, s orbital
l = 1 , p orbital
l = 2, d orbital
in 2nd energy shell the number of orbitals are 0,1 etc.
5s-
Principal quantum number n = 5
Azimuthal quantum number l = 0
6p
Principal quantum number n = 6
Azimuthal quantum number l = 1
4d
Principal quantum number n = 4
Azimuthal quantum number l = 2
