Answer:
How to determine the mole of LiOH required to react with 20 moles of CO₂ per day
CO₂ + 2LiOH —> Li₂CO₃ + H₂O
From the balanced equation above,
1 mole of CO₂ required 2 moles of LiOH.
Therefore,
20 moles of CO₂ will require = 20 × 2 = 40 moles of LiOH
How to determine the mole of LiOH required by two astronauts for 3 days
Mole of LiOH for 1 person per day = 40 moles
Mole of LiOH for 2 persons per day = 2 × 40 = 80 moles
Mole of LiOH for 2 persons for 3 days = 80 × 3 = 240 moles
Explanation:
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The only products will be carbon dioxide and water.
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O
Answer:
The dog should be given half of 100 mg tablet in the morning and another half of 100 mg tablet in an evening.
Explanation:
Weight of the dog = 50 pounds = 22.68 kg
1 kg = 2.205 pounds
Amount of daily dose prescribed by doctor = 4.4 mg/kg
Total mount of dose = 4.4 mg/kg × 22.68 kg = 99.79 mg
99.79 mg ≈ 100 mg
49.89 mg ≈ 50 mg
So, according to doctor prescription dog should be given half 100 mg tablet in the morning and another half of 100 mg tablet in an evening.
Answer:
Explanation:
Methanol's molecular weight: 
Methanol's heat of vaporization: 
Ideal gas heat capacity (Cp):
where R is the gas constant
The heat needed to vaporize and bring the gs to 210°C is:
Answer:
The temperature would be too cold
Explanation:
