Cells, Cell Division)

describe the trends in the atomic size, location energy and electrongavity from left to right across a period in periodic table

Elenna [48]

Atomic size decreases in a period but the ionization energy and electronegativity increases across a period.

<h3>Describe the trends in the atomic size, ionization energy and electronegativity?</h3>

Atomic radius decreases across a period because of nuclear charge increases whereas atomic radius of atoms generally increases from top to bottom within a group because there is again an increase in the positive nuclear charge.

Ionization energy increases when we move from left to right across an period and decreases from top to bottom.

Electronegativity also increases from left to right across a period and decreases from top to bottom.

So we can conclude that atomic size decreases in a period but the ionization energy and electronegativity increases across a period.

Learn more about Electronegativity here: brainly.com/question/24977425

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3 0

1 year ago

WHO CAN HELP ME ON THIS NEED OF HELP! Due soon !

Otrada [13]

Answer:

Runoff from a cattle ranch

7 0

2 years ago

Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802

Anvisha [2.4K]

Answer:

1 gramo de metano aporta 50.125 kilojoules.

1 gramo de metano aporta 48.246 kilojoules.

Explanation:

La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo ( $Q$ ), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto ( $\bar {Q}$ ), en kilojoules por mol, dividido por su masa molar ( $M$ ), en gramos por mol:

$Q = \frac{\bar Q}{M}$ (1)

A continuación, analizamos cada caso:

Metano

$Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }$

$Q = 50.125\,\frac{kJ}{g}$

1 gramo de metano aporta 50.125 kilojoules.

Octano

$Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }$

$Q = 48.246\,\frac{kJ}{mol}$

1 gramo de metano aporta 48.246 kilojoules.

3 0

2 years ago

What are things that amorphous and crystalline have in common?

Juliette [100K]

Six brick land llwnswel

5 0

2 years ago

Freon, a very useful refrigerant, is produced in the following reaction:

Svetach [21]

Answer:

The chemistry will need 2*10⁶ moles of antimony trifluoride.

Explanation:

The balanced reaction is:

3 CCl₄ (g) + 2 SbF₃ (s) → 3 CCl₂F₂(g) + 2 SbCl₃ (s)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

CCl₄: 3 moles
SbF₃: 2 moles
CCl₂F₂: 3 moles
SbCl₃: 2 moles

You can apply the following rule of three: if by reaction stoichiometry 3 moles of freon are produced by 2 moles of antimony trifluoride, 3*10⁶ moles of Freon are produced from how many moles of antimony trifluoride?

$moles of antimony trifluoride=\frac{3*10^{6} moles of freon*2 moles of antimony trifluoride}{3 moles of freon}$

moles of antimony trifluoride= 2*10⁶

<u><em>The chemistry will need 2*10⁶ moles of antimony trifluoride.</em></u>

8 0

3 years ago