Answer:
H-O* + CH3-CH3 ----> H-O-CH2-CH2*
Answer:
0.6 moles NH₃
Explanation:
The reaction that takes place is:
First we <u>determine the limiting reactant</u>:
- 0.35 mol N₂ would react completely with (3*0.35) 1.05 moles of H₂. There are not as many H₂ moles, so H₂ is the limiting reactant.
Then we <u>convert H₂ moles (the limiting reactant) to NH₃ moles</u>, keeping in mind the <em>stoichiometry of the reaction</em>:
- 0.90 mol H₂ *
= 0.6 moles NH₃
Answer:
a. Molarity= 
b. Molality= 
Explanation:
Hello,
In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

Moreover, the molality:

Best regards.