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lina2011 [118]
3 years ago
11

Find the wavelength of radio waves of frequency 200kHz

Physics
2 answers:
lys-0071 [83]3 years ago
6 0
For any wave, Wavelength = (speed) / (frequency)

For radio waves, Speed = about 3x10⁸ meters per sec ("speed of light")

So Wavelength = (3 x 10⁸ m/s) / (200 x 10³ /sec) = <em>1,500 meters</em>
Gala2k [10]3 years ago
3 0
\lambda = \frac{c}{f}
λ - wavelength, c - the speed of light, f - frequency

f=200 \ kHz= 200 000 \ Hz \\ \\&#10;\lambda=\frac{300 000 \ [\frac{km}{s}]}{200 000 \ [Hz]}=\frac{3}{2}=1.5 \ [km]

The wavelength of these waves is 1.5 km.
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A spherical shell contains three charged objects. The first and second objects have a charge of − 14.0 nC and 33.0 nC , respecti
matrenka [14]

Explanation:

Formula depicting relation between total flux and total charge Q is as follows.

              \phi  = \frac{Q}{\epsilon_{o}}    (Gauss's Law)

Putting the given values into the above formula as follows.

            Q = \phi \times \epsilon_{o}

                = -953 Nm^{2}/C \times 8.854 \times 10^{-12}

                = -8.4 \times 10^{-9} C

                = -8.4 nC

Therefore, when the unknown charge is q  then,

         -14.0 nC + 33.0 nC + q = -8.4 nC

               q = -27.4 nC

Thus, we can conclude that charge on the third object is -27.4 nC.

7 0
3 years ago
Which red line shows the same action spectrum corrected for the unequal number of photons emitted across the visible spectrum?.
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<h3>What is visible spectrum?</h3>

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The question is incomplete as the details are missing. The visible spectrum is composed of red, orange,yellow,  green, blue, violet, indigo.

Learn more about the visble spectrum: brainly.com/question/1596783

3 0
2 years ago
A crate is placed on an adjustable, incline board. the coefficient of static friction between the crate and the board is 0.29.
sasho [114]

Let the angle be Θ (theta)

Let the mass of the crate be m.

a) When the crate just begins to slip. At that moment the net force will be equal to zero and the static friction will be at the maximum vale.

Normal force (N) = mg CosΘ

μ (coefficient of static friction) = 0.29

Static friction = μN = μmg CosΘ

Now, along the ramp, the equation of net force will be:

mg SinΘ - μmg CosΘ = 0

mg SinΘ = μmg CosΘ

tan Θ = μ

tan Θ = 0.29

Θ = 16.17°

b) Let the acceleration be a.

Coefficient of kinetic friction = μ = 0.26

Now, the equation of net force will be:

mg sinΘ - μ mg CosΘ = ma

a = g SinΘ - μg CosΘ

Plugging the values

a = 9.8 × 0.278 - 0.26 × 9.8 × 0.96

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a = 0.278 m/s^2

Hence, the acceleration is 0.278 m/s^2

7 0
3 years ago
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