C is the most reasonable answer
Answer:
Explanation:
Given
wall is 10 m from student
8 m high
Therefore student should launch at an angle \theta such that its maximum height is 8 m and its range is 20 m
For maximum height(h)
Range (R)
divide 1 & 2
Answer:
work done would be I don't know
To solve this problem we will apply the concepts related to Newton's second law for which the product of mass and acceleration is defined as the force applied to an object. Mathematically this is,
Here,
Net external Force
m = Mass of the body
a = Acceleration
The net force on the body would be given by the difference between the ascending force and the weight, therefore,
Here,
F = Upward Force
W = Weight
The Weight is,
Then the is
Finally replacing at the first equation we have,
Therefore the acceleration of the stone is