Answer:
Molecular formula = C₄F₈
Explanation:
Given data:
Empirical formula of compound = CF₂
Molar mass of compound = 200.4 g/mol
Molecular formula of compound = ?
Solution:
Formula:
Molecular formula = n ( empirical formula)
n = Molar mass of compound / empirical formula mass
empirical formula mass = CF₂ = 12+19×2 = 50 g/mol
n = 200.4 g/mol / 50 g/mol
n = 4
Molecular formula = n ( empirical formula)
Molecular formula = 4 ( CF₂)
Molecular formula = C₄F₈
Answer:
H3PO4 Mol mass..
= (3 x H1 = 3) + (1 x P31 = 31) + (4 x O16 = 64). = 98g/mol.
a)..Hydrogen: = 3 / 98 = 0.0306 x 100% = 3.06%.
b)..Phosphorus = 31/98 = 0.3162 x 100% = 31.63%.
c)..Oxygen = 64/98 = 0.6531 x 100% = 65.31%.
(Total = 100% H3PO4).
Explanation:
Find the molar mass of all the elements in the compound in grams per mole.
Find the molecular mass of the entire compound.
Divide the component's molar mass by the entire molecular mass.
You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.
Answer:
The pH os the substance is 1,92.
Explanation:
The pH is a measure that gives us an idea of the acidity or alkalinity of a solution. It is calculated as:
pH = -log (H +)= -log (1.2 x 10^-2 )=1,92
The pH scale ranges from values of 0 to 14 (less than 7.0 is acidic and greater than 7.0 is basic, a pH = 7.0 is neutral). In this case, the substance is acidic.
It’s is 130 that is the answer!!!!