The mass of water is calculated as follows
find the moles of each reagent
that is moles = mass/molar mass
for H2s = 84.7/ 34= 2.485 moles
O2 = 78.4 / 32 = 2.45 moles
since 2 moles of H2S react with 3 moles of O2 therefore 2.45 moles of oxygen will be used up therefore O2 is the limiting reagent and H2S is in excess
2H2S + 3O2 ----->2So2 + 2H2O
by use of mole ratio between O2 and H20 which is 3:2 the moles of H2O is therefore = 2.45 x2/3= 1.63 moles of H2O
mass of H2O = moles x molar mass
= 1.63 g x 18g/mol = 29.4 g
If the volume exiting the large intestine were 364 mL, then it would most likely indicate a case of diarrhea. This condition may lead to dehydration.
<h3>Diarrhea: causes and diagnosis</h3>
Diarrhea is an unhealthy condition that occurs when the body excretes an excessive amount of water.
Diarrhea must be treated because this condition can lead to dehydration (it may even lead to death in severe cases).
Both diarrhea and vomiting may lead to the loss of body fluids.
Learn more about diarrhea dehydration here:
brainly.com/question/10268680
Answer: The answer is 68142.4 Pa
Explanation:
Given that the initial properties of the cylindrical tank are :
Volume V1= 0.750m3
Temperature T1= 27C
Pressure P1 =7.5*10^3 Pa= 7500Pa
Final properties of the tank after decrease in volume and increase in temperature :
Volume V2 =0.480m3
Temperature T2 = 157C
Pressure P2 =?
Applying the gas law equation (Charles and Boyle's laws combined)
P1V1/T1 = P2V2/T2
(7500 * 0.750)/27 =( P2 * 0.480)/157
P2 =(7500 * 0.750* 157) / (0.480 *27)
P2 = 883125/12.96
P2 = 68142.4Pa
Therefore the pressure of the cylindrical tank after decrease in volume and increase in temperature is 68142.4Pa
Answer:
Hydrocarbon combustion refers to the chemical reaction where a hydrocarbon reacts with oxygen to create carbon dioxide, water, and heat. Hydrocarbons are molecules consisting of both hydrogen and carbon. ... Methane combining with 2 oxygen to form carbon dioxide, water and heat.
Answer is s orbital. Hopes this helps
