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Arada [10]
3 years ago
13

Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0

.771 g of biphenyl (C12H10) in 25.0 g of cyclohexane?
Chemistry
1 answer:
Elza [17]3 years ago
4 0

Answer: 2.49^0C

Explanation:

Depression in freezing point is:

T_f^0-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = freezing point of solution = ?

T^o_f =  freezing point of solvent (cyclohexane) = 6.50^oC

k_f =  freezing point constant  of  solvent (cyclohexane)  = 20.0^oC/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute (biphenyl) = 0.771 g

w_1 = mass of solvent (cyclohexane) = 25.0 g

M_2 = molar mass of solute (biphenyl) =

Now put all the given values in the above formula, we get:

(6.50-T_f)^oC=1\times (20.0^oC/m)\times \frac{(0.771g)\times 1000}{154\times (25.0g)}

(6.50-T_f)^oC=4.01

T_f=2.49^0C

Therefore, the freezing point of a solution made by dissolving 0.771 g of biphenyl in 25.0 g of cyclohexane is 2.49^0C

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