Given:
K = 0.71 = Kp
The reaction of sulphur with oxygen is
S(s) + O2(g) ---> SO2(g)
initial Pressure 6.90 0
Change -x +x
Equilibrium 6.90-x x
Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)
4.899 - 0.71x = x
4.899 = 1.71x
x = 2.86 atm = pressure of SO2 formed
temperature = 950 C = 950 + 273.15 K = 1223.15 K
Volume = 50 L
Let us calculate moles of SO2 formed using ideal gas equation as
PV = nRT
R = gas constant = 0.0821 L atm / mol K
putting other values
n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles
Moles of Sulphur required = 1.42 moles
Mass of sulphur required or consumed = moles X atomic mass of sulphur
mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg of sulphur
Electron configuration is the electron distribution in the molecular and atomic orbital. An element with configuration ns²np¹ will be in the 3A group. Thus, option B is correct.
<h3>What is electronic configuration?</h3>
The electronic configuration has been the arrangement and distribution of the sub-atomic particle, an electron in the atomic shells.
The electronic configuration given is, ns²np¹. Here, there are three valence electrons in the outermost orbit. As it has been known that the number of the valence electron gives the number of the group.
Therefore, option B. 3A group or 13 group is the correct option.
Learn more about electronic configuration here:
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Your question is incomplete, but most probably your full question was, An element with the general electron configuration for its outermost electrons of ns2np1 would be in which group?
a. 2a
b. 3a
c. 4a
d. 5a
e. 8a
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<h2>The required option d) "specific heat" is correct.</h2>
Explanation:
- To raise the temperature of any substance or material of certain mass to respective temperature it requires some amount of heat.
- Specific heat is the amount of heat necessary to raise the temperature of the substance of 1 gram to 1 Kelvin.
- It is the amount of heat which is required to raise the temperature per unit mass to per unit temperature.
- Thus, the required "option d) specific heat" is correct.
Answer:
35.6 liters at STP
Explanation:
The molar mass of carbon dioxide is about 44.01 g/mol. The volume of a mole of ideal gas at STP is 22.4 L, so the volume of 70.0 g will be ...
(70.0g)/(44.01 g/mol)·(22.4 L/mol) ≈ 35.6 L