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Oksana_A [137]
3 years ago
14

What is the acceleration of an object that goes from 3 m/s to 5 m/s in 8 s?

Chemistry
2 answers:
nikdorinn [45]3 years ago
8 0

Answer: 0.25m/s2

Explanation:

Acceleration is change in velocity with time

V = final velocity = 5m/s

U =Initial velocity = 3m/s

t = time = 8s

a = Acceleration =?

a = V — U / t

a = (5 — 3) / 8

a = 2/8

a = 0.25m/s2

netineya [11]3 years ago
5 0
Acceleration formula is Vf-Vi divided by time. Final velocity = 5, Initial Velocity = 3, and time is 8.
So, do in a calculator (5-3) divided by 8.
Or step by step:
5-3 = 2
2/8 = 0.25
And units for acceleration is m/s/s (m/s squared) so it is 0.25m/s^2 (squared)
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Explain how the presence of several oxygen atoms ina compound containing an-OH group can make the compound acidic.
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The factors to consider

Two of the factors which influence the ionisation of an acid are:

<span>the strength of the bond being broken,the stability of the ions being formed.</span>

In these cases, you seem to be breaking the same oxygen-hydrogen bond each time, and so you might expect the strengths to be similar.

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3 years ago
Which organisms have greater variation and produce offspring through asexual reproduction?
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8 0
3 years ago
Potassium chlorate decomposes into potassium chloride and oxygen gas. How many grams of oxygen are produced when 1.06 grams of p
kifflom [539]

The amount of oxygen that are produced when 1.06 grams of potassium chlorate decompose completely is 0.64 grams.

<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

Moles of potassium chlorate = 1.66g / 122.5g/mol = 0.0135mole

Given chemical reaction is:

2KClO₃ → 2KCl + 3O₂

From the stoichiometry of the reaction, it is clear that:

2 moles of KClO₃ = produces 3 moles of O₂

0.0135 moles of KClO₃ = produces (3/2)(0.0135)=0.02 moles of O₂

Mass of oxygen = (0.02mol)(32g/mol) = 0.64 g

Hence produced mass of oxygen is 0.64 grams.

To now more about mass & moles, visit the below link:
brainly.com/question/18983376

#SPJ1

5 0
2 years ago
As the temperature of seawater increases from 15o C to 20o C, sound velocity through the seawater
polet [3.4K]
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7 0
3 years ago
Read 2 more answers
A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

7 0
3 years ago
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