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Zielflug [23.3K]
3 years ago
8

How does the ocean influence climate?

Physics
1 answer:
enot [183]3 years ago
7 0
Im going too have too go with A. because it does say that warm water currentswill have a warmer climate and it will place it in the cold water current.
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How fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5j​
ankoles [38]

Answer:

E=0.5 m v^2

2*10^-5 = 0.5 1000*v^2

4*10^-5=1000v^2

4*10^-8=v^2

2*10^-4 =v

7 0
3 years ago
What is a living organism? Give a few examples.
zhuklara [117]

Answer:

It's a individual form of life. Examples of this are bacterium , protists and fungus

7 0
2 years ago
A 1200 kg car traveling east at 4.5 m/s crashes into the side of a 2100 kg truck that is not moving. During the collision, the v
Rasek [7]

Answer:

Explanation:

This is a simple Law of Momentum Conservation problem of the inelastic type. The equation for this is

[m_1v_1+m_2v_2]_b=[(m_1+m_2)v]_a  Filling in:

[1200(4.5)+2100(0)]=[(1200+2100)v] which simplifies to

5400 + 0 = 3300v

so v = 1.6 m/s to the east, choice B

6 0
2 years ago
If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of t
Ronch [10]

Since the acceleration is constant, the average velocity is simply the average of the initial and final velocities of the body:

v_{avg} = \frac{v_f+v_i}{2}=\frac{30 m/s+13 m/s}{2}=21.5 m/s

We can proof that the distance covered by the body moving at constant average velocity v_{avg} is equal to the distance covered by the body moving at constant acceleration a:

- body moving at constant velocity v_{avg}: distance is given by

S=v_{avg}t = \frac{v_f+v_i}{2}t

- body moving at constant acceleration a=\frac{v_f-v_i}{t}: distance is given by

S=v_i t+ \frac{1}{2}at^2 = v_i t + \frac{1}{2}\frac{v_f-v_i}{t}t^2=(v_i+\frac{1}{2}(v_f-v_i))t=\frac{v_f+v_i}{2}t

7 0
2 years ago
Read 2 more answers
A train travels 99 kilometers in 2 hours, and then 90 kilometers in 3 hours. What is its average speed?
Agata [3.3K]

Average speed =

(total distance)/(total time)

Average speed = (99+90)/(2+3)

That's (189 km) / (5 hr)

Average speed = 37.8 km/hr

3 0
2 years ago
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