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sveticcg [70]
3 years ago
12

Describe how the periodic table differentiates between metals and nonmetals.

Chemistry
1 answer:
dmitriy555 [2]3 years ago
6 0
Most of the elements on the periodic table are metals...generally speaking...metals occur on the left side of the periodic table, and non-metals occur on the right side of the periodic table... 

<span>...check out the periodic table locate at: http://www.elementsdatabase.com/ </span>
<span>look at the second colored periodic table...take a look at the key for this table...notice that the non-metals are colored white or red...all other elements would therefore be metals... </span>
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A 250 cm^3 solution containing 1,46 g of sodium chloride is added to an excess of silver nitrate solution. The reaction is given
faust18 [17]

Answer:

The mass of the precipitate  that AgCl is 3.5803 g.

Explanation:

a) To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (NaCl) = 1.46 g

Molar mass of sulfuric acid = 58.5 g/mol

Volume of solution = 250 cm^3 =250 mL

1 cm^3= 1 ml

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{1.46g\times 1000}{58.5g/mol\times 250}\\\\\text{Molarity of solution}=0.09982 M

0.09982 M is the concentration of the sodium chloride solution.

b) NaCl (aq)+AgNO_3 (aq)\rightarrow AgCI(s)+NaNO_3(aq)

Moles of NaCl = \frac{1.46 g}{58.5 g/mol}=0.02495 mol

according to reaction 1 mol of NaCl gives 1 mol of AgCl.

Then 0.02495 moles of NaCl will give:

\frac{1}{1}\times 0.02495 mol=0.02495 mol of AgCl

Mass of 0.02495 moles of AgCl:

0.02495 mol\times 143.5 g/mol=3.5803 g

The mass of the precipitate  that AgCl is 3.5803 g.

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3 years ago
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Explanation:

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kakasveta [241]

Answer:

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Alexeev081 [22]
Molar mass 

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n = mass / molar mass

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m = 3.00 * 60.0

m = 180 g of <span>C₂H₄O₂ 

hope this helps!</span>
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