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wolverine [178]
3 years ago
9

The earth’s radius is 6.37 × 10 6 m ; it rotates once every 24 hours. What is the earth’s angular speed? Viewed from a point abo

ve the north pole, is the angular velocity positive or negative? What is the speed of a point on the equator? What is the speed of a point on the earth’s surface halfway between the equator and the pole? (Hint: What is the radius of the circle in which the point moves?)
Physics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

a) the angular speed of the Earth's rotation is <em>7.272 × 10⁻⁵ rad/s.</em>

<em></em>

b) Viewed from the North Pole, Earth's angular speed rotates in an anticlockwise direction. Therefore, the <em>angular velocity is positive.</em>

<em></em>

c) Earth's speed at a point on the equator is <em>463.23 m/s.</em>

<em></em>

d)  the speed of a point on the earth’s surface halfway between the equator and the pole is <em>231.61 m/s.</em>

Explanation:

a) The angular speed of the Earth's rotation is:

ω = 2π / T

where

T is the period

ω = 2π / (24 hr × (3600 s / 1 hr))

<em>ω = 7.272 × 10⁻⁵ rad/s</em>

b) Viewed from the North Pole, Earth's angular speed rotates in an anticlockwise direction. Therefore, the <em>angular velocity is positive.</em>

c) Earth's speed at a point on the equator is:

v = r × ω

v = (6.37 × 10⁶ m) × (7.272 × 10⁻⁵ rad/s)

<em>v = 463.23 m/s</em>

d) The radius of the circle in which the point moves is half of Earth's radius. Therefore,

r = 1/2(6.37 × 10⁶ m)

r = 3.19 × 10⁶ m

Therefore, the speed of a point on the earth’s surface halfway between the equator and the pole is:

v = r × ω

v = (3.19 × 10⁶ m) × (7.272 × 10⁻⁵ rad/s)

<em>v = 231.61 m/s</em>

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