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Degger [83]
1 year ago
10

The electron configuration of bromine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 classify electrons in each.

Chemistry
1 answer:
bulgar [2K]1 year ago
7 0

Bromine has the following electron configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5. categorize the electrons in each. Answer for video: The video player is loaded.

On the periodic chart, row 5, column 7, is where you can find a chemical element that was identified in 1811. It has a proton count of 53 and an atomic mass of 126.9. Iodine's atom, then, contains 53 electrons in the following configuration: 1s2, 2s2, 2p6, 3s2, 3d10, 4p6, 5s2, 4d10, 5p5 (Kr 4d10 5s2 5p5). Cu Z = 29 has an electrical arrangement of 1s2 2s2 2p6 3s2 3p6 3d10 4s1. Copper (Co) has the following electron configuration: 1s2 2s2 2p6 3s3 3p6 4s2 3d7. If a chemist were to refer to Copper by its subshell, they would abbreviate this notation to "3d7."

To learn more about electrons please click on below link

brainly.com/question/1255220

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An atom of boron has an atomic number of 5 and an atomic mass of 11. the atom contains
kirill [66]
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3 years ago
Write the steps for calculating molar mass.
Marizza181 [45]

Answer:

Explanation:

1) Find number of each of the type of atom that is present in the compound, using the chemical formula .

2) Then multiply number of atoms of each element that is present in the compound with the atomic weight of each of the element

3) Add everything together and add the units (grams/mole ) after the number

Let finds that of water

Chemical formula of water is (H20 )

hydogens atoms= 2

oxygen atom= 1

Atomic weight for Hydrogen= 1

Atomic weight for Oxygen= 16

Total number of atoms of Hydrogen from the formula (H2O)= 2

Total number of atoms of Oxygen from the formula (H2O)= 1

the molar mass=

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5 0
3 years ago
PLEASE ANSWER...........WILL MARK BRAINLIEST!!!!!!!
ANTONII [103]

Answer:

<h2>The Alkali metal halide may precipitate or there may be no change at all</h2>

Explanation:

       Alkali metal cations are positively charged. Halogen anions are negatively charged. When a solution of Alkali metal cations is added to a solution of Halogen anions, there are two possibilities :

  • The alkali metal halide( salt formed from reation of the two ions) may precipitate if the Ionic product is higher than the Solubility product.
  • However, if it can remain in the solution, it will remain so. No chemical changes happen with respect to these both ions. Nothing willl happen.

   There is no reaction happening in either of the cases because both species are already in ionic form before addition, hence they continue to be in this form.

3 0
3 years ago
Suppose the formation of iodine proceeds by the following mechanism:
NARA [144]

Answer:

Overall reaction

H2(g) + 2ICI(g) -----> I2(g) +2HCl(g)

Overall Rate = k1[H2] [ICl]

Explanation:

Overall reaction

H2(g) + 2ICI(g) -----> I2(g) +2HCl(g)

The overall reaction is the sum of the two two reactions shown in the question. After the two reactions are summed up properly, this overall reaction equation his obtained.

Since K1<<K2 it means that step 1 is slower than step 2. Recall that the rate if reaction depends on the slowest step of the reaction. Hence

Overall Rate = k1[H2] [ICl]

3 0
3 years ago
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