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Degger [83]
1 year ago
10

The electron configuration of bromine is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 classify electrons in each.

Chemistry
1 answer:
bulgar [2K]1 year ago
7 0

Bromine has the following electron configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5. categorize the electrons in each. Answer for video: The video player is loaded.

On the periodic chart, row 5, column 7, is where you can find a chemical element that was identified in 1811. It has a proton count of 53 and an atomic mass of 126.9. Iodine's atom, then, contains 53 electrons in the following configuration: 1s2, 2s2, 2p6, 3s2, 3d10, 4p6, 5s2, 4d10, 5p5 (Kr 4d10 5s2 5p5). Cu Z = 29 has an electrical arrangement of 1s2 2s2 2p6 3s2 3p6 3d10 4s1. Copper (Co) has the following electron configuration: 1s2 2s2 2p6 3s3 3p6 4s2 3d7. If a chemist were to refer to Copper by its subshell, they would abbreviate this notation to "3d7."

To learn more about electrons please click on below link

brainly.com/question/1255220

#SPJ4

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Gas particles are pumped into a rigid steel container at a constant temperature. Which statement describes the change in pressur
Masteriza [31]

Answer:

The pressure inside the container would increase with each additional pump.

Explanation:

  • From the general gas law of ideal gases:

<em>PV = nRT,</em>

where, P is the pressure of the gas.

V is the volume of the gas.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas.

  • As clear from the gas law; the pressure of the gas is directly proportional to the no. of moles of the gas.

<em>P α n.</em>

  • As gas particles are pumped into a rigid steel container, the no. of moles of the gas will increase.

So, the pressure of the gas will increase.

<em>Thus, the right choice is: The pressure inside the container would increase with each additional pump.</em>

8 0
3 years ago
What mass of carbon dioxide is formed when 1.75 mol of ethane burns completely in oxygen?
dybincka [34]

Answer:

There is a mass of 154 Grams of Carbon Dioxide.

Explanation:

One mole is equal to 6.02 × 10^23 particles.

This means we have 1.05 X 10^24 total particles of Ethane.

Each ethane particle contains 2 carbon atoms.

If every particle of ethane is burned, we will end up with 2.10 x 10^24 molecules of Carbon Dioxide (Particles of Methane x 2, since each Methane particle contains 2 carbon atoms)

Carbon Dioxide has a molar mass of 44.01 g/mol

So if we take our amount of Carbon Dioxide molecules and divide it by 1 mole, ((2.10 x 10^24)/(6.02 x 10^23) = 3.49) we find that we have 3.49 moles of Carbon Dioxide.

Now all we need to do is multiply our moles of carbon dioxide(3.49) by it's molar mass(44.01) while accounting for significant digits.

What you should end up with is 154 Grams of Carbon Dioxide.

Hope this helps (And more importantly I hope I didn't make any errors in my math lol)

As a side note this is all assuming that this takes place at STP conditions.

3 0
3 years ago
A student made the following diagram to represent cellular respiration.
Ratling [72]
The correct answer is A, Water is not used up during this process. This is because when cellular respiration occurs oxygen and glucose combine. When this takes place water is left behind when carbon is separated from glucose. Because water is being left behind it is not being used up in this process. 
3 0
3 years ago
Read 2 more answers
Determine whether each molecule is polar or nonpolar.
JulsSmile [24]
A) Sulfur dichloride (SCl₂) is polar molecule because is <span>bent with asymmetric charge distribution around the central atom (S).
b) </span>Sulfur tetrachloride (SCl₄) is polar because there is<span> lone electron pair around the sulfur.
c) </span>Bromine pentachloride (BrCl₅) is polar because dipole moment do not cancel. 
6 0
3 years ago
Explain how chemists overcome the problem of low yield In industry
mrs_skeptik [129]

High temperature and pressure produce the highest rate of reaction. However, this must be balanced with the high cost of the energy needed to maintain these conditions. Catalysts increase the rate of reaction without affecting the yield. This can help create processes which work well even at lower temperatures.

I hope this helps you.

8 0
3 years ago
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