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Alja [10]
3 years ago
14

If the concentration of a reactant in a mixture is doubled and the reaction rate increases by a factor of eight, the reaction or

der with respect to that reactant is
Chemistry
1 answer:
Ronch [10]3 years ago
8 0
Answer: Three

When the reactant concentration is increased, generally the reaction rate will be increased too. But the magnitude of the increase can differ in various reaction. In this case, 2x concentration will result in 8x reaction rate. The order will be:
2^x= 8
2^x= 2^3
x=3
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Identify from the following list of molecules and ions which behave as Lewis acids: CO2, NH3, BCl3, Fe3+. (A) CO2 and NH3 (B) NH
Anettt [7]

Answer : The correct option is, (D) CO₂, BCl₃, and Fe³⁺

Explanation :

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

(a) CO_2

It is a Lewis-acid because it can accepts electron pairs.

(b) NH_3

It is not a Lewis-acid because it can not accepts electron pairs but it is a base because it can donates and accept hydrogen ion.

(c) BCl_3

It is a Lewis-acid because it can accepts electron pairs because it has an incomplete octet and an empty 2p orbital.

(d) Fe^{3+}

It is a Lewis-acid because it can accepts electron pairs.

Hence, the ions which behave as Lewis acids are, CO₂, BCl₃, and Fe³⁺

6 0
3 years ago
Evaluate (754 mm)/(41 s) to three significant figures and express answer in SI units using an appropriate prefix.
Mama L [17]

1.14m x MG is the answer

5 0
3 years ago
Give the formula and name for the iconic compounds formed from the following pairs of elements:
Fudgin [204]

(1) Give the formula and name for the iconic compounds formed from the following pairs of elements:

A. KCl potassium chloride

B. ZnO zinc oxide

(2) Give the formula for each of the following ionic compounds:

A. KClO₃ potassium chlorate

B. MgSO₄ magnesium sulfate

C. KNO₃ potassium nitrate

(3) Give the name of the following covalent compounds:

A. SO₂ sulfur dioxide

B. CCl₄ carbon tetrachloride

C. SiS₂ silicon disulfide

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4 0
3 years ago
How many moles of Na3PO4 are in 820. grams of it?
kotegsom [21]

Answer:Hello

D is correct

Explanation:

4 0
3 years ago
Magnesium burns in air with a dazzling brilliance to produce magnesium oxide: 2 Mg(s) + O2(g) → 2 MgO(s) How many moles of O2 ar
TEA [102]

Answer:

1.05 mols of O2 gas

Explanation:

For this type of problem, it's important to understand what the balanced Chemical equation tells us:

<h3><u>Balanced Chemical equations</u></h3>

Let's look at the balanced chemical equation:

2Mg(s)+O_2(g)-- > 2MgO(s)

This equation two sides of the reaction arrow.  On the left are the reactants (things you start with, and that react during the chemical reaction), and on the right side are products (things that are produced during the chemical reaction that you end with).

The numbers in front of each compound tell how many of molecules are involved for a full reaction without anything left over.  A "mol" is a large quantity (6.022*10^{23}), in this case, of molecules , since it's unlikely you're only taking a single molecule of each substance (it would be so tiny, you wouldn't even know you were doing the reaction).

So,for every 2 moles of Magnesium used, we'll also need 1 mole of Oxygen, and it will produce 2 moles of Magnesium Oxide.

In a way, during the reaction it's almost like 2 moles of Magnesium is equal to 1 mole of Oxygen and is equal to 2 moles of Magnesium Oxide:

2 mol Mg(s)=1mol O_2(g)=2molMgO(s)

From here, we can build some unit ratios, to convert between the known quantity of moles we have, and find the unknown quantity of moles that are requested.

<h3><u>Finding the right unit ratio</u></h3>

We know that we are looking at 2.10 mol of Magnesium, so we want a unit ratio with moles of Mg on the bottom.  <u>We want to find moles of O2</u>, <u>so we want a unit ratio of moles of O2 on top</u>.

The unit ratio we want is the middle part of the equation, divided by the left part of the equation.

2 mol Mg(s)=1mol O_2(g)\\\frac{2 mol Mg(s)}{2 mol Mg(s)}=\frac{1mol O_2(g)}{2 mol Mg(s)}\\1=\frac{1mol O_2(g)}{2 mol Mg(s)}

Since this quantity is 1, it is a unit ratio and can be multiplied to other things to change their units (for this problem).

<h3><u>Finding the answer</u></h3>

Starting with what we know, and multiplying by our unit ratio:

2.10 mol Mg(s)*\frac{1mol O_2(g)}{2 mol Mg(s)}=1.05mol O_2(g)

Notice that the units from the first quantity cancel with the units on the bottom of the fraction, leaving only the unit on top of the fraction ... the exact units we wanted!

So, 1.05mols of O2 would be consumed during the reaction if exactly 2.10moles of Magnesium are burned.

4 0
2 years ago
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