All categories

2 years ago

Nồng độ mol của 200ml dung dịch Nacl chứa 0,5 mol chất tan là :

Chemistry

2 answers:

DaniilM [7]2 years ago

8 0

Answer:

2,5m

Explanation:

c=n:v

solniwko [45]2 years ago

7 0

Answer:

Explanation:

2,5M

You might be interested in

"Inert" xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH° values for xenon difluorid

svp [43]

The average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.

Given:

ΔH° of xenon difluoride (XeF2) = -105 kJ/mol

ΔH° of xenon tetrafluoride (XeF4)= -284 kJ/mol

ΔH° of xenon hexafluoride (XeF6) = -402 kJ/mol

The bond energy of Xe-F in XeF2 can be calculated as follows,

As we know that

ΔH° = ΔH°(bond formed) + ΔH°(bond broken)

The chemical reaction for the formation of XeF2 can be written in such a way,

Xe (g) + F2 (g) → XeF2 (g)

= [1 mol F2 (159 kJ/mol)] + [2(-Xe-F)] - 105 kJ/mol

= 159 kJ/mol + 2(-Xe-F) - 264 kJ/mol

= 2(-Xe-F)

Xe-F = 132 kJ/mol

Thus, we concluded that the average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.

learn more about bond energy:

brainly.com/question/11653058

#SPJ4

3 0

1 year ago

A student obtains the following data: Mass of empty, dry graduated cylinder: 21.577 g Volume added of NaCl solution: 4.602 mL Ma

klasskru [66]

<u>Answer:</u> The density of NaCl solution is 3.930 g/mL

<u>Explanation:</u>

We are given:

Mass of cylinder, $m_1$ = 21.577 g

Mass of NaCl and cylinder combined, M = 39.664 g

Mass of NaCl, $m_2$ = $(M-m_1)=(39.664-21.577)g=18.087g$

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Mass of NaCl = 18.087 g

Volume of NaCl solution = 4.602 mL

Putting values in above equation, we get:

$\text{Density of NaCl}=\frac{18.087g}{4.602mL}\\\\\text{Density of NaCl}=3.930g/mL$

Hence, the density of NaCl solution is 3.930 g/mL

7 0

2 years ago

Find the mass of each of these substances? 2.40 mol NaOH

damaskus [11]

Na = 23 x 2.40 = 55.2
O = 16 x 2.40 = 38.4
H = 1 x 2.40 = 2.40

55.2 + 38.4 + 2.4 = 96

2.40 mol of NaOH = 96 amu

4 0

3 years ago

Based on the solubility chart, which of the listed salts is the most soluble at 25 degrees Celsius?

VashaNatasha [74]

I think it's Potassium iodide because it has the highest solubility at 25°C.

4 0

3 years ago

Read 2 more answers

4. Why can't the subscripts be changed in a chemical equation in chemistry

neonofarm [45]

If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is

4 0

2 years ago