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AVprozaik [17]
3 years ago
12

Butane is used as a fuel in disposable lighters. Write the Lewis structure for each isomer of butane.

Chemistry
1 answer:
AVprozaik [17]3 years ago
3 0

Answer:

Lewis structure for isomers of butane has been given below.

Explanation:

Butane is a saturated alkane with molecular formula C_{4}H_{10}. Due to different positing of methyl groups, positional isomerism exists in butane.

Butane has two positional isomers with same molecular formula. One is n-butane and another one is isobutane. Lewis structures of these two isomers have been given below.

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sleet_krkn [62]

Answer:- 29.6 moles of carbon.

Solution:- We have been given with 3.7 moles of C_8H_11NO_2 and asked to calculate the moles of C.

Looking at the formula of the compound, there are 8 carbons in it means 1 mol of he compound has 8 moles of C. So, if we multiply the given moles of the compound by 8 then we get the moles of C.

3.7molC_8H_11NO_2(\frac{8molC}{1molC_8H_11NO_2})

= 29.6 mol C

Hence. there are 29.6 moles of C in 3.7 moles of  C_8H_11NO_2  .

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3 years ago
Compare natural selection to evolution. Be sure to justify your response in two or more complete sentences.
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3 years ago
Fusion reactors are more desirable than fission because:
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I believe it is A)fuel is more readily available:)
4 0
3 years ago
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My swimming pool is rectangular (16 feet by 34 feet) and has a depth of 6 feet. Lets imagine that my pool water is full to the t
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Answer:

Number of moles of photons required = 5.04 × 10⁴ moles

Explanation:

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Where m is mass of substance,  c is specific heat capacity,  ΔT is temperature difference

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Volume of water = Volume of swimming pool

Volume of water = 16 × 34 × 6 ft³ = 3264 ft³

1 ft³ = 28316.8 cm³; 3264 ft³ = 28316.8 × 3264 = 92426035.2 cm³

Density of water = 1 g/cm³

Mass of water = 92426035.2 cm³ × 1 g/cm³ = 92426035.2g

ΔT = 80°C - 50°C = 30°C, c = 4.18 J/g/K

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Number of moles of photons required = 5.04 × 10⁴ moles

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Answer:

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