Question

student conducted an experiment and find the density of an ICEBERGE. A students than recorded the following readings. Mass 425 25   g Volume 405 15   mL What experimental value should be quoted for the density of the ICEBERG? Compare your answer with the density of water, which is 3 1.00 10  kg . Show any calculations necessary to justify your answer

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

The experimental value of density is   $\rho = 1.05*10^{3} \ kg/m^3 \pm 101 \ kg/m^3$

Comparing it with the value of density of water ($1.0*10^{3} \ kg/m^3$) we can see that the density of ice is greater

Explanation:

From the question we are told

    The mass is $M = (425 \pm 25) \ g =(0.425 \pm 0.025) \ kg$

   The volume is $V = (405 \pm 15 ) \ mL = (0.000405 \pm 1.5*10^{-5}) \ m^3$

The experimental value of density is mathematically evaluated as

        $\rho = \frac{M}{V}$

       $\rho = \frac{0.425}{0.000405}$

       $\rho = 1.05 *10^{3} \ kg/m^3$

The possible error in this experimental value of density is mathematically evaluated as

        $\frac{\Delta \rho}{\rho} = \frac{\Delta M}{M} +\frac{\Delta V}{V}$

substituting value

         $\frac{\Delta \rho}{1.05*10^{3}} = \frac{0.025}{0.425} +\frac{1.5*10^{-5}}{0.000405}$

        $\Delta \rho = 101 \ kgm^{-3}$

Thus the experimental value of density is

             $\rho = 1.05*10^{3} \ kg/m^3 \pm 101 \ kg/m^3$