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Wittaler [7]
3 years ago
7

The crankshaft in a race car goes from rest to 3000 rpm in 3.0 s . (a) What is the crankshaft's angular acceleration?

Physics
1 answer:
Talja [164]3 years ago
7 0

Answer:

75 rotations

Explanation:

f0 = 0, f = 3000 rpm = 50 rps, t = 3 s

(a) use first equation of motion for rotational motion

w = w0 + α t

2 x 3.14 x 50 = 0 + α x 3

α = 104.67 rad/s^2

(b) Let θ be the angular displacement

use second equation of motion for rotational motion

θ = w0 t + 1/2 α t^2

θ = 0 + 0.5 x 104.67 x 3 x 3

θ = 471.015 rad

The angle turn in one rotation is 2 π radian.

Number of rotation = 471.015 / (2 x 3.14) = 75 rotations

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When do you gotta turn it in?
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2 years ago
A water-balloon launcher with a mass of 1.75 kg is suspended on a wire. It fires a 1.25 kg balloon to the east at a velocity of
poizon [28]

Answer:

8.6 to west

Explanation:

8 0
2 years ago
The concentration of Biochemical Oxygen Demand (BOD) in a river just downstream of a wastewater treatment plant’s effluent pipe
shtirl [24]

Answer:

The BOD concentration 50 km downstream when the velocity of the river is 15 km/day is 63.5 mg/L

Explanation:

Let the initial concentration of the BOD = C₀

Concentration of BOD at any time or point = C

dC/dt = - KC

∫ dC/C = -k ∫ dt

Integrating the left hand side from C₀ to C and the right hand side from 0 to t

In (C/C₀) = -kt + b (b = constant of integration)

At t = 0, C = C₀

In 1 = 0 + b

b = 0

In (C/C₀) = - kt

(C/C₀) = e⁻ᵏᵗ

C = C₀ e⁻ᵏᵗ

C₀ = 75 mg/L

k = 0.05 /day

C = 75 e⁻⁰•⁰⁵ᵗ

So, we need the BOD concentration 50 km downstream when the velocity of the river is 15 km/day

We calculate how many days it takes the river to reach 50 km downstream

Velocity = (displacement/time)

15 = 50/t

t = 50/15 = 3.3333 days

So, we need the C that corresponds to t = 3.3333 days

C = 75 e⁻⁰•⁰⁵ᵗ

0.05 t = 0.05 × 3.333 = 0.167

C = 75 e⁻⁰•¹⁶⁷

C = 63.5 mg/L

5 0
2 years ago
Ask Your Teacher Two long, straight wires are parallel and 11 cm apart. One carries a current of 2.9 A, the other a current of 5
dsp73

Answer:

The magnitude of force per unit length of one wire on the other is 2.7945\times 10^{-5}\ N and the direction is away from one another

The magnitude of force per unit length of one wire on the other is 2.7945\times 10^{-5}\ N and the direction is towards each other.

Explanation:

\mu_0 = Vacuum permeability = 4\pi\times 10^{-7}\ N/A^2

i_1 = Current in first wire = 2.9 A

i_2 = Current in second wire = 5.3 A

r = Gap between the wires = 11 cm

Force per unit length

F_{12}=F_{21}=\frac{\mu_0 i_1i_2}{2\pi r}\\ =\frac{4\pi\times 10^{-7}\times 2.9\times 5.3}{2\pi 0.11}\\ =2.7945\times 10^{-5}\ N

The magnitude of force per unit length of one wire on the other is 2.7945\times 10^{-5}\ N and the direction is away from one another

F_{12}=F_{21}=\frac{\mu_0 i_1i_2}{2\pi r}\\ =\frac{4\pi\times 10^{-7}\times 2.9\times 5.3}{2\pi 0.11}\\ =2.7945\times 10^{-5}\ N

The magnitude of force per unit length of one wire on the other is 2.7945\times 10^{-5}\ N and the direction is towards each other.

7 0
2 years ago
Could someone please explain what makes up the electromagnetic spectrum? Thank you.
faust18 [17]
These types include gamma rays, x-rays, ultraviolet, infrared, microwaves and radio waves. Together with visible light, all these types of radiation make up what we call the electromagnetic spectrum - the complete spectrum of radiation.
3 0
3 years ago
Read 2 more answers
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