Predicting the volume of a gas, given its temperature and pressure p<span>roperties.</span>
Here's a fun and useful factoid:
The ratio of the voltages on a transformer is the same
as the ratio of the number of turns in each winding.
So the ratio of (345 to the secondary turns) is (115V to 24V).
That's a proportion.
(115/24) = (345/x)
I'll bet you can take it and solve it from here.
Just cross-multiply in the proportion and etc. etc.
The object will remain at rest
Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Here net force is zero
An object with a net force of zero acting on it will remain at rest, if initially at rest, or it will maintain a constant velocity.
F=MA
Force F=0
Than Acceleration A=0
With zero Acceleration stationary object will remain at rest.
Hence Remain at rest is the correct answer
Learn more about Newton's law of motion here
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Answer:
There is net loss of gravitational energy .
Explanation:
When Xanaxa is on the ground , her potential energy is assumed to be zero . When she leaps to a height of 153 m , she gains gravitational energy . When she dives and reaches the surface , she loses potential energy and on reaching the ground her potential energy becomes zero . When she further goes down inside ground to a depth of 17.5 m , she loses potential energy further . Her potential energy becomes less than zero or negative .
Ultimately her potential energy changes from zero to negative in the whole process . So there is net loss of potential energy .
The pressure drop in pascal is 3.824*10^4 Pascals.
To find the answer, we need to know about the Poiseuille's formula.
<h3>
How to find the pressure drop in pascal?</h3>
- We have the Poiseuille's formula,
where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, 
is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
- Thus, the pressure drop will be,
Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4 Pascals.
Learn more about the Poiseuille's formula here:
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