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algol [13]
2 years ago
11

Imagine that a new planet is discovered with two moons of equal mass: Moon A and Moon B. The mass of the new planet is greater t

han the combined mass of its moons. Moon A is farther away from the new planet than Moon B. What is the planet's gravitational pull on Moon A compared to the planet's gravitational pull on Moon B?
The planet's gravity repels Moon A with a greater force than it repels Moon B, which is why Moon A is farther away.

The gravitational pull on Moon B is greater than on Moon A because Moon B is closer to the new planet than Moon A.

The gravitational pull on Moon B is greater than on Moon A because Moon B is farther away from the new planet than Moon A.

The gravitational pull on Moon A is the same as the gravitational pull on Moon B because distance does not affect the planet's gravity.
Chemistry
1 answer:
kobusy [5.1K]2 years ago
3 0

Answer: The gravitational pull on Moon B is greater than on Moon A because Moon B is closer to the new planet than Moon A.

Explanation:

The gravitational force exerted by the two objects on each other is inversely proportional to the square of the distance between the objects.

F=G\frac{mM}{r^2}

F = gravitational force or pull

G = gravitational constant on that planet

M =  mass of the object-1

m = mass of object-2(Mass of Moon-A or Moon-B)

r = distance between two objects

Force\propto \frac{1}{r^2}

With decease in distance 'r' the force between the object increases or vice versa.So, from this we can say that the gravitational pull on Moon-B is more than the gravitational pull on Moon-A because the Moon B is closer than the Moon-A from the new planet.

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Answer:
            Dispersion Forces are found between n-Pentane (CH₃-CH₂-CH₂-CH₂-CH₃) and n-Hexane (CH₃-CH₂-CH₂-CH₂-CH₂-CH₃).

Explanation:
                   Dispersion Forces are present and developed by those compounds which are non-polar in nature. In given statement n-Pentane and n-Hexane both are non-polar in nature as the electronegativity difference between Hydrogen atoms and Carbon atoms is less than 0.4. 
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8 0
3 years ago
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The rate law for the decomposition of phosphine () is It takes 135. s for 1.00 M to decrease to 0.250 M. How much time is requir
vova2212 [387]

Answer:

189.71 secs

Explanation:

We know that decomposition is a first order reaction;

So;

ln[A] = ln[A]o - kt

But;

[A]o = 1.00 M

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t =135 s

Hence;

ln[A] -  ln[A]o = kt

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k = ln(1) - ln(0.250)/135

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k = 1.386/135

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So time taken now will be;

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t = 1.0986 + 0.7985/0.01

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Answer:

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Explanation:

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