Answer:
(a)
(b)
Explanation:
Hello.
(a) In this case, since the initial volume is 18.5 dm³ and the final volume is 21 dm³ (18.5 +2.5), we can compute the work at constant pressure as shown below:
Which is negative as it expands against the given pressure.
(b) Moreover, of the process is carried out reversibly, the pressure can change, therefore, we need to compute the work via:
Whereas the moles are computed from the given mass of argon:
Thus, the work is:
Regards.
Answer:
<h2>675 N</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 45 × 15
We have the final answer as
<h3>675 N</h3>
Hope this helps you
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