Answer:
The specific heat of the metal is 0.212 J/(g°C).
Explanation:
We can calculate the specific heat of the metal by the following equilibrium:
In the above equation, we have that the heat loses by the metal (b) is gained by the water (a).
: is the water's mass = 72.0 g
: is the specific heat of water = 4.184 J/(g°C)
: is the initial temperature of the water = 19.2 °C
: is the final temperature of the water = 25.5 °C
: is the metal's mass = 141 g
: is the specific heat of metal =?
: is the initial temperature of the metal = 89.0 °C
: is the final temperature of the water = 25.5 °C
Therefore, the specific heat of the metal is 0.212 J/(g°C).
I hope it helps you!
Answer:
vinegar or stomach acid im not quite sure
Explanation:
Answer:
<h2>252.9 kPa</h2>
Explanation:
The new pressure can be found by using the formula
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
From the question we have
We have the final answer as
<h3>252.9 kPa</h3>
Hope this helps you
Answer:
4.3 × 10⁻⁵ M s⁻¹
Explanation:
Step 1: Given data
- Rate constant (k): 2.20 × 10⁷ M⁻¹s⁻¹
- Concentration of NO ([NO]): 3.3 × 10⁻⁶ M
- Concentration of O₃ ([O₃]): 5.9 × 10⁻⁷ M
- First order with respect to both NO and O₃
Step 2: Write the balanced reaction
NO + O₃ ⇒ NO₂ + O₂
Step 3: Calculate the reaction rate
The rate law is:
rate = k × [NO] × [O₃]
rate = 2.20 × 10⁷ M⁻¹s⁻¹ × 3.3 × 10⁻⁶ M × 5.9 × 10⁻⁷ M
rate = 4.3 × 10⁻⁵ M s⁻¹
