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VMariaS [17]
3 years ago
10

As a pendulum bob swings back and forth several times, the maximum height it reaches becomes less and less.

Physics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

A or B

Explanation:

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Which of the following sequences describes the path by which electrons travel downhill energetically in aerobic respiration
Vlad1618 [11]

Answer:

glucose → NADH → electron transport chain → oxygen.

Explanation:

Aerobic respiration is also called as cellular respiration, in which electrons are picked up by the FADH, and NADH from the food. Then through a proton pump electrons are transferred to the electron transport chain, in this, the activity of the proton pump generates an electrochemical gradient, then this gradient used by the ATP synthase enzyme to produce ATP.

In aerobic respiration, the last acceptor of electron is oxygen. An electron is donated to oxygen for the formation of the water.

5 0
4 years ago
Transfer payments are used to redistribute money to various segments of society. please select the best answer from the choices
mote1985 [20]

Answer:

True

Explanation:

You pay back what you owe for what youve purchased

7 0
2 years ago
What is the force of a 24.52 kg Television dropped on Pluto (acceleration of 0.59 m/s2)
inna [77]

The force of gravity on the object is 14.47 N

Explanation:

The weight of an object (which is the force of gravity experienced by an object) at a certain location is given by

F=mg

where

m is the mass of the object

g is the acceleration of gravity at the location of the object

IN this problem, we have:

m = 24.52 kg (mass of the object)

g=0.59 m/s^2 (acceleration of gravity on Pluto)

Substituting, we find the force of gravity on the object:

F=(24.52)(0.59)=14.47 N

Learn more about forces and weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

7 0
3 years ago
Which of these stopped operating in 2011
Vladimir [108]
D. space shuttle program
8 0
4 years ago
Read 2 more answers
Problem 9: Suppose you wanted to charge an initially uncharged 85 pF capacitor through a 75 MΩ resistor to 90.0% of its final vo
Bingel [31]

Answer:

t=14.678\times 10^{-3}s

Explanation:

Given:

Capacitance, C = 85 pF = 85 × 10⁻¹² F

Resistance, R = 75 MΩ = 75×10⁶Ω

Charge in capacitor at any time 't' is given as:

Q=Q_o(1-e^{-\frac{t}{RC}})

where,

Q₀ = Maximum charge = CE

E = Initial voltage

t = time

also, Q = CV

V= Final voltage = 90% of E = 0.9E

thus, we have

C\times 0.9E=CE(1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})

or

0.9=1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}

or

e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}=1-0.9=0.1

taking log both sides, we get

ln(e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})=ln(0.1)=ln(\frac{1}{10})

or

-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}=-ln(10)

or

t=75\times 10^6\ \times\ 85\times 10^{-12}\times ln{10}

or

t=14.678\times 10^{-3}s

3 0
3 years ago
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