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vlabodo [156]
3 years ago
12

Please help!!! Is it balanced or unbalanced?

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
6 0

Hey there!

I believe the answer you are looking for is Unbalanced!

If I am incorrect I am very sorry and would love any feedback.

Have a nice day, and Happy Halloween!

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A sample of a substance has a mass of 4.2 grams and a volume of 6 milliliters
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Answer:

Density of the substance is 0.7

Explanation:

4.2/6 = 0.7

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The elemental symbol of gold is denoted on the periodic table as being Au.
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A gas evolved during the fermentation of alcohol had a volume of 19.4 L at 17 °C and 746 mmHg. How many moles of gas were collec
AlexFokin [52]

Answer:- 0.800 moles of the gas were collected.

Solution:- Volume, temperature and pressure is given for the gas and asks to calculate the moles of the gas.

It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:

PV=nRT

Since it asks to calculate the moles that is n, so let's rearrange this for n:

n=\frac{PV}{RT}

V = 19.4 L

T = 17 + 273 = 290 K

P = 746 mmHg

we need to convert the pressure from mmHg to atm and for this we divide by 760 since, 1 atm = 760 mmHg

P=746mmHg(\frac{1atm}{760mmHg})

P = 0.982 atm

R = 0.0821\frac{atm.L}{mol.K}

Let's plug in the values in the equation to get the moles.

n=\frac{0.982atm*19.4L}{0.0821\frac{atm.L}{mol.K}*290K}

n = 0.800 moles

So, 0.800 moles of the gas were collected.

4 0
3 years ago
If the pressure of a gas sample is quadrupled and the absolute temperature is doubled, by what factor does the volume of the sam
Natasha_Volkova [10]

Answer:

D) 1/2

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given,

P₂ = 4P₁

T₂ = 2T₁

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{P_1}\times {V_1}}{T_1}=\frac {{4\times P_1}\times {V_2}}{2\times T_1}

V_2=\frac{1}{2}\times V_1

<u>The volume change by half of the original.</u>

7 0
3 years ago
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What is kinetic energy of a 155 kg object moving at speed of 20 m/s
Novay_Z [31]

Answer:

KE = 1/2*m*v^2

KE = 1/2*150kg*(20 m/s)^2

KE = 75kg * 400m²/s²

KE = 30,000 kg*m²/s²

KE = 30,000 N*m

KE = 30,000 J

Explanation:

Hope this helped.

A brainliest is always appreciated.

4 0
2 years ago
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