<u>Answer:</u> The molarity of 
ions in the solution is 0.306 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Mass of solute 
= 15.6 g
Molar mass of = 295.6 g/mol
Volume of solution = 345 mL
Putting values in above equation, we get:
As, 1 mole of produces 1 mole of copper (II) ions and 2 moles of nitrate ions.
So, molarity of ions = (2 × 0.153) = 0.306 M
Hence, the molarity of ions in the solution is 0.306 M
Aldehydes and ketones having
α-hydrogen atoms, undergoes aldol condensation, in present of base (NaOH).
The initial product formed during this reaction is
β-hydroxy alcohol, which then undergoes dehydration to form
α,β-unsaturated aldehyde or ketone.
In present case, 3,3-dimethyl-2-butanone has 2α-hyrogen atom, while methylcyclopentane-1-carbaldehyde has 1α-hydrogen atom. So the major product formed during cross aldol condensation reaction of these reactants is:
5-hydroxy-4,4-dimethly-1-(2-methylcyclopentyl)pent-1-en-3-one. The complete reaction product formed is shown below.
.07! you divide 7 by 100%
Amount of a substance (called the solute) that dissolves in a unit volume of a liquid substance (called the solvent) to form a saturated solution under specified conditions of temperature and pressure.Solubility is expressed usually as moles of solute per 100 grams of solvent.
