Ask question

Ask question

All categories

2 years ago

8

30 Which term identifies a type of nuclear reaction?(1) transmutation (3) deposition

2 answers:

tensa zangetsu [6.8K]2 years ago

8 0

The answer is <span>(1) transmutation

Transmutation is a turning of one element into another which occurs when proton numbers change. It can be either natural transmutation when there is only one reactant or artificial transmutation when there is another reactant which causes proton numbers change</span>

Vikki [24]2 years ago

7 0

The answer is Transmutation

You might be interested in

Why are space probes and other unmanned crafts more commonly used for space investigations than space crafts with crews of astro

Crank

All of these are correct.

4 0

2 years ago

How many single covalent bonds can halogens form?

Simora [160]

One single covalent bond, hope this helps!

4 0

2 years ago

4,600,000,000,000 in scientific notation

BabaBlast [244]

4.6to the twelth power plus ten or something like that it has been a while since I have done the scientific notation but where ever you put in the number of zeros. is twelve

6 0

2 years ago

Which [H+] value describes a neutral solution?

alina1380 [7]

Answer:

It's A) 10 -7 M

4 0

2 years ago

A Cu2+ solution is prepared by dissolving a 0.4749 g piece of copper wire in acid. The solution is then passed through a Walden

Luda [366]

Answer:

Concentration of $Cr_2O_7^{2-}$ = 0.03101 M

Concentration of $MnO_4^-$ = 0.03721 M

Explanation:

A)

The reduction for $Cr_2O_7^{2-}$ is;

$Cr_2O_7^{2-} + 14 H ^+ _{(aq)} + 6 e^- -----> 2 Cr^{3+} _{(aq)}+7H_2O _{(l)}$

$Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-$

6 moles of $Cu ^+$ = 1 mole of $Cr_2O_7^{2-}$

number of moles of Cu reacted = $\frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }$

number of moles of Cu reacted = $\frac{0.4749}{63.55}$

number of moles of Cu reacted = 0.00747 mole

number of moles of $Cr_2O_7^{2-}$ reacted = $\frac{0.00747}{6}$

number of moles of $Cr_2O_7^{2-}$ reacted = 0.001245 mole

Concentration of $Cr_2O_7^{2-}$ = $\frac{number \ of moles }{Volume}$

Given that the volume = 40.15 mL = $40.15 *10^{-3}$ ; we have:

Concentration of $Cr_2O_7^{2-}$ = $\frac{0.001245}{40.15*10^{-3}}$

Concentration of $Cr_2O_7^{2-}$ = 0.03101 M

B)

The reduction for $MnO_4^-$ is;

$MnO_4^- + 8H^+ + 5 e^- -----> Mn^{2+} + 4H_2O$

$Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-$

5 moles of $Cu ^+$ = 1 mole of $Cr_2O_7^{2-}$

number of moles of Cu reacted = $\frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }$

number of moles of Cu reacted = $\frac{0.4749}{63.55}$

number of moles of Cu reacted = 0.00747 mole

number of moles of $MnO_4^-$ reacted = $\frac{0.00747}{5}$

number of moles of $MnO_4^-$ reacted = 0.001494 mole

Concentration of $MnO_4^-$ = $\frac{number \ of moles }{Volume}$

Given that the volume = 40.15 mL = $40.15 *10^{-3}$ ; we have:

Concentration of $MnO_4^-$ = $\frac{0.001494 }{40.15*10^{-3}}$

Concentration of $MnO_4^-$ = 0.03721 M

3 0

3 years ago