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andre [41]
3 years ago
5

A weight suspended from a spring is seen to bob up and down over a total distance of 20 centimeters twice each second.

Physics
1 answer:
Tom [10]3 years ago
6 0

"Twice each second" means "2 per second".  <em>Frequency = 2 Hz.</em>

<em>Period </em>= time for one bounce = <em>1 second</em>

Amplitude = distance between "not stretched" and "greatest stretch".

<em>Amplitude =  10 centimeters</em>


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How many cells must be connected in series to give the 350 v a large catfish can produce?
victus00 [196]
Each electrocyte can produce 110 mv.
110 m/V=0.110V
n(0.110)=350
n=3182 (rounded)
3 0
3 years ago
The moon is slowly moving away from the earth. What will eventually happen to the gravitational pull force between the earth and
sesenic [268]
The gravitational pull will reduce, because the moon is moving further away from the centre of the earth. In other words, the further an object is from the centre of the earth, the weaker the gravitational pull that will be exerted on it. 
6 0
3 years ago
A ball rolls off a desk at a speed of 2 m/s and lands 0.50 seconds later.
Hoochie [10]

Answer:

(a) The ball lands <u>1 m</u> ahead of the desk's base.

(b) The height of the desk is <u>1.225 m.</u>

Explanation:

Given:

Initial velocity of the ball is, u_{0}=2\ m/s

Time of flight of the ball is, t=0.50\ s

(a)

Let the ball fall at a distance of x from the base of the desk and let the height of the desk be y.

The given motion of the ball is a projectile motion that can be divided into 2 mutually perpendicular directions.

Now, considering only the horizontal motion of the ball. The ball not under the influence of any force in the horizontal direction.

Therefore, the distance covered by the ball horizontally is given as:

x=v_0\times t\\x=2\times 0.50=1\ m

So, the ball lands 1 m ahead of the desk's base.

(b)

Now, consider only the vertical motion of the ball. The ball is under the influence of gravity.

So, vertical distance can be obtained  using Newton's equations of motion.

We use the following equation of motion:

y-y_0=u_{oy}t+\frac{1}{2}gt^2

Where,

y_{0}\rightarrow \textrm{initial vertical position of ball}\\u_{oy}\rightarrow \textrm{initial vertical velocity}\\g\rightarrow \textrm{acceleration due to gravity}\\y\rightarrow \textrm{final position of ball vertically}

Here, as the ball leaves the desk horizontally, initial velocity is only in the horizontal direction and doesn't have any component in the vertical direction. So, u_{oy}=0\ m/s

Plug in y_0=h,y=0,g=-9.8,u_{oy}=0,t=0.5. Solve for h.

0-h=0+\frac{1}{2}(-9.8)(0.5)^2\\-h=-4.9\times 0.25\\h=1.225\ m

Therefore, the height of the desk is 1.225 m.

6 0
3 years ago
If an object weighs 300 N on earth, what is it’s mass on the moon?
inna [77]

Answer:

The mass of the object on the Moon (and anywhere else) is about 30.61kg. Please see more detail below.

Explanation:

Weight is the gravitational force exerted on the object and is a function of mass and gravitational acceleration:

(weight) = (mass) x (gravitational acceleration)

We are to find the mass, knowing the weight on Earth to be 300N:

(mass) = (weight on Earth) / (gravitational acceleration on Earth) = 300N / 9.8 m/s^2 = 30.61 kg

The mass of the object is 30.61kg.

The mass of the object is independent of gravity. Therefore the answer to the question "What is its mass on the Moon" is 30.61kg.

If the question were what is its weight on the Moon, the answer would be

(weight on Moon) = (mass) x (grav.accel. on Moon) = 30.61kg x 1.62 m/s^2 = 49.59N

which is about 1/6 of the object's weight on the Earth.

4 0
3 years ago
What is the magnitude of the electric field in a region where the potential is given by the expression V = ax2 + b where a = −50
sweet [91]

Answer:

E = 1000 x

Explanation:

The electric potential and the electric field are related by the formula

        dV = - E . dx

Bold represents vectors.

The point represents the scalar product, in this case we calculate the electric field in the x-axis and the potential is also in this axis so the scalar product is reduced to the algebraic product

        E = dV /dx

Let's make the derivative

        E = - 2ax

Let's replace the values

        E = -2 (-500) x

        E = 1000 x

5 0
3 years ago
Read 2 more answers
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