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4 years ago

5

When a pendulum is held high and taut and then is released the pendulum begins to swing. What’s the correct order of the energy

transformations in this example?

1 answer:

Shkiper50 [21]4 years ago

5 0

1 gravitational PE

2 kinetic enrege

3thermal energy

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Which landscape will erode more quickly? Assume the same precipitation and average temperature in each landscape.

Artemon [7]

Answer:

B. Landscape B

Explanation:

Shale is fine sediment pressed together to form rock.

Sandstone is larger (sand-grain-sized) sediment cemented together to form rock.

Shale erodes faster, as evidenced by the second attachment. That attachment shows erosion of a rock face consisting of interbedded shale and sandstone. The shale has receded significantly, leaving the sandstone layers with space between them.

5 0

3 years ago

0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary for

Paladinen [302]

Assuming the accleration applied was constant, we have

$v=v_0+at\implies v_0+20.0\,\dfrac{\mathrm m}{\mathrm s}=v_0+a(0.10\,\mathrm s)$

$\implies20.0\,\dfrac{\mathrm m}{\mathrm s}=a(0.10\,\mathrm s)$

$\implies a=200\,\dfrac{\mathrm m}{\mathrm s^2}$

Then the force applied to the ball is given by

$F=ma=(0.45\,\mathrm{kg})\left(200\,\dfrac{\mathrm m}{\mathrm s^2}\right)$

$\implies F=90\,\dfrac{\mathrm{kg}\,\mathrm m}{\mathrm s^2}=90.\,\mathrm N$

8 0

3 years ago

( WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST AND SHOWS WORK) A car weighs 15300 N. What is its mass?

mylen [45]

Answer:

Mass, m = 1561.23kg

Explanation:

Given the following data;

Weight = 15300N

We know that acceleration due to gravity is equal to 9.8m/s²

To find mass;

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, the weight of an object is given by the formula;

$Weight, W = mg$

Where;

m represents the mass of an object measured in kilograms.

g is the acceleration due to gravity measured in meters per seconds square.

Substituting into the equation, we have;

$15300 = m*9.8$

$m = \frac {15300}{9.8}$

<em>Mass, m = 1561.23 Kg</em>

<em>Therefore, the mass of the car is 1561.23 kilograms.</em>

7 0

3 years ago

Two long, parallel wires separated by 2.00 cm carry currents in opposite directions. The current in one wire is 1.75 A, and the

Natasha_Volkova [10]

The force per unit length between the two wires is $6.0\cdot 10^{-5} N/m$

Explanation:

The magnitude of the force per unit length exerted between two current-carrying wires is given by

$\frac{F}{L}=\frac{\mu_0 I_1 I_2}{2\pi r}$

where

$\mu_0 = 4\pi \cdot 10^{-7} Tm/A$ is the vacuum permeability

$I_1, I_2$ are the currents in the two wires

r is the separation between the two wires

For the wires in this problem, we have

$I_1 = 1.75 A$

$I_2 = 3.45 A$

r = 2.00 cm = 0.02 m

Substituting into the equation, we find

$\frac{F}{L}=\frac{(4\pi \cdot 10^{-7})(1.75)(3.45)}{2\pi (0.02)}=6.0\cdot 10^{-5} N/m$

Learn more about current and magnetic fields:

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#LearnwithBrainly

4 0

4 years ago

A liquid of density 1270 kg/m3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the f

FinnZ [79.3K]

Answer:

${P_2}-P_1=49.99\ KPa$

Explanation:

$v_1=9.43\ m/s$

$d_1=11.7\ cm/s$

$d_2=17.5\ cm/s$

From continuity equation

$A_1v_1=A_2v_2$

$v_1d_1^2=v_2d_2^2$

$v_2=\dfrac{9.43\times 11.7^2}{17.5^2}$

$v_2=4.21\ m/s$

$\dfrac{P_1}{\rho g}+\dfrac{v_1^2}{2g}+y_1=\dfrac{P_2}{\rho g}+\dfrac{v_2^2}{2g}+y_2$

${P_1}+\rho\dfrac{v_1^2}{2}+\rho y_1g={P_2}+\rho\dfrac{v_2^2}{2}+\rho y_2g$

$\rho\dfrac{v_1^2}{2}+\rho y_1g -\rho\dfrac{v_2^2}{2}-\rho y_2g={P_2}-P_1$

$1270\times \dfrac{9.43^2}{2}+1270\times 0\times 10 -1270\times\dfrac{4.21^2}{2}-1270\times 0.175\times 10={P_2}-P_1$

${P_2}-P_1=49.99\ KPa$

4 0

3 years ago