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tia_tia [17]
3 years ago
8

A pool is 59.8 m long and 26.6 m wide. If the average depth of water is 3.70 ft, what is the mass (in kg) of water in the pool?

Enter your answer in scientific notation. The density of water is 1.0 g/mL.
Chemistry
1 answer:
klio [65]3 years ago
7 0

Given :

Length , l = 59.8 m.

Breadth , b  = 26.6 m.

Depth , d = 3.7 ft .

Density of water , \rho=1\ g/ml=1000\ kg/m^3 .

To Find :

Mass of water in pool .

Solution :

First we will covert depth into m from ft .

1\ ft =0.3\ m

For ,

3.7\ ft=0.3\times 3.7\ m\\3.7\ ft=1.11\ m

So , volume of pool is :

V=59.8\times 26.6\times 1.11\ m^3\\\\V=1765.65\ m^3

We know , density is given by :

\rho=\dfrac{m}{V}

So , m=\rho V

Putting given values in above equation :

m=1000\times 1765.65\ kg\\\\m=1.77\times 10^6\ kg

Hence , this is the required solution.

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5.1169 mol of Ne is held at 0.9148 atm and 911 K. What is the volume of its container in liters?
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<h3>Boyle's  Law</h3>

Given Data

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We know that the relationship between pressure and temperature is given as

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Substituting our given data to find the volume we have

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2 years ago
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<h3>What is activation energy?</h3>

Activation energy in chemistry is the energy required to initiate a chemical reaction.

Chemical reactions involve the breaking of chemical bonds in substances called reactants to form new substances called products.

The energy required to break the bond in the existing reactants thus elevating these substances to a state of high activation is known as activation energy.

Therefore, it can be said that energy required to break existing chemical bonds in reactants is called the activation energy.

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