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tia_tia [17]
3 years ago
8

A pool is 59.8 m long and 26.6 m wide. If the average depth of water is 3.70 ft, what is the mass (in kg) of water in the pool?

Enter your answer in scientific notation. The density of water is 1.0 g/mL.
Chemistry
1 answer:
klio [65]3 years ago
7 0

Given :

Length , l = 59.8 m.

Breadth , b  = 26.6 m.

Depth , d = 3.7 ft .

Density of water , \rho=1\ g/ml=1000\ kg/m^3 .

To Find :

Mass of water in pool .

Solution :

First we will covert depth into m from ft .

1\ ft =0.3\ m

For ,

3.7\ ft=0.3\times 3.7\ m\\3.7\ ft=1.11\ m

So , volume of pool is :

V=59.8\times 26.6\times 1.11\ m^3\\\\V=1765.65\ m^3

We know , density is given by :

\rho=\dfrac{m}{V}

So , m=\rho V

Putting given values in above equation :

m=1000\times 1765.65\ kg\\\\m=1.77\times 10^6\ kg

Hence , this is the required solution.

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Suppose of nickel(II) chloride is dissolved in of a aqueous solution of potassium carbonate. Calculate the final molarity of chl
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Answer: Molarity of chloride anion = 0.32 M

<em>Note: the question is missing some values. The full question is given below;</em>

<em>Suppose 7.26 g of nickel(II) chloride is dissolved in 350 mL of a 0.50 M aqueous solution of potassium carbonate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the nickel(II) chloride is dissolved in it. Be sure your answer has the correct number of significant digits.</em>

Explanation:

Molarity or molar concentration is the number of moles (mol) of component per volume (liters) concentration of solution in mol/L or M

The mass of nickel (II) chloride is 7.26 g.

The volume of potassium carbonate is 350 mL = 0.35 L

The molarity of potassium carbonate solution is 0.50 M

The reaction of nickel (II) chloride and potassium carbonate is given below.

NiCl₂(aq) + KCO₃(aq) --------> KCl(aq) +NiCO₃(s)

The dissociation of nickel (II) chloride is given below.

NiCl₂   -----> Ni²⁺ + 2Cl⁻

The molar mass of nickel (II) chloride is  129.6 g/mol

The moles of nickel (II) chloride can be calculated by the formula given below;

No of moles  = mass(g) / molar mass (g/mol)

No of moles = 7.26 / 129.6 = 0.056 moles

Therefore, molarity of NiCl₂ = 0.056 moles/ 0.35 L = 0.16 M

The molarity of 1 mole nickel (ii) chloride is 0.16 m and according to dissociation of nickel (II) chloride, 1 mole of nickel (II) chloride gives 2 moles of chloride anion.

Therefore, the molarity of chloride anion = 0.16 * 2 = 0.32 M

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Explanation:

To solve this problem we need to use the combined gas law:

    <u>P₁V₁</u>   =    <u>P₂V₂</u>

      T₁              T₂

Data

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