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mash [69]
3 years ago
9

According to Faraday's law, a coil in a strong magnetic field must have a greater induced emf in it than a coil in a weak magnet

ic field. According to Faraday's law, a coil in a strong magnetic field must have a greater induced emf in it than a coil in a weak magnetic field. True False
Physics
1 answer:
Len [333]3 years ago
7 0

Answer:

TRUE

Explanation:According to Faraday’s equation, the induced emf is directly proportional to the rate of change of magnetic flux.

EMF=−NΔΦΔt, where N is number of turns of wire round the coil, ΔΦ rate of change of magnetic flux and t is the time measured in seconds.

Magnetic flux is affected by the field strength and the area covered by the coil, if magnetic field increases the induced electromotive force will increase.

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A coil of wire containing N turns is in an external magnetic field that is perpendicular to the plane of the coil and it steadil
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The Resultant Induced Emf in coil is 4∈.

Explanation:

Given that,

A coil of wire containing having N turns in an External magnetic Field that is perpendicular to the plane of the coil which is steadily changing. An Emf (∈) is induced in the coil.

To find :-

find the induced Emf if rate of change of the magnetic field and the number of turns in the coil are Doubled (but nothing else changes).

So,

   Emf induced in the coil represented by formula

                          ∈  =   -N\frac{d\phi}{dt}                                  ...................(1)

                                          Where:

                                                    .   \phi = BAcos\theta     { B is magnetic field }

                                                                                 {A is cross-sectional area}

                                                    .  N = No. of turns in coil.

                                                    .  \frac{d\phi}{dt} = Rate change of induced Emf.

Here,

Considering the case :-

                                    N1 = 2N  &      \frac{d\phi1}{dt} = 2\frac{d\phi}{dt}

Putting these value in the equation (1) and finding the  new emf induced (∈1)

                           

                                      ∈1 =-N1\times\frac{d\phi1}{dt}

                                      ∈1 =-2N\times2\frac{d\phi}{dt}

                                       ∈1 =4 [-N\times\frac{d\phi}{dt}]

                                        ∈1 = 4∈             ...............{from Equation (1)}      

Hence,

The Resultant Induced Emf in coil is 4∈.        

                           

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