Answer:
The answer is NH3 and CH3OH
Explanation:
The basic rule of a reaction is "like dissolves like" and for a homogenous mixture to form, there must be some common properties related to bonding.
1. KI and Hg
Normally mercury tends to form amalgam which is not a homogeneous solution.
2. LICL and C6H14
One is non polar and other is polar which makes the homogeneous reaction not possible.
3. C3H8 and C2H5OH
Both are miscible but will not develop homogeneous solution as propane is gas at normal temperature.
4. F2 and PF3
Flourine is highly electronegative and will repel fellow flourine making it not possible for homogeneous solution
5. NH3 and CH3OH
Both have same type of bonding and can react homogeneously.
<h3>
Answer:</h3>
= +0.43 V
<h3>
Explanation:</h3>
The two standard reduction potentials are;
Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E₀ = +0.77 V
Cu²⁺(aq) + 2e⁻ → Cu(s) E₀ = +0.34 V
The overall reaction is;
Fe³⁺(aq) + Cu(s) → Fe²⁺(aq) + Cu²⁺(aq)
To calculate the standard cell potential of the overall reaction, we use the equation;
Ecell = E redu, cathode - E red, anode
From the reaction; Copper lost electrons to form copper ions (Cu²⁺) (Oxidation) while Fe³⁺ gained electrons to form Fe²⁺ (reduction)
Therefore;
E cell = + 0.77 v - (+0.34 v)
= + 0.43 V
Hence, the standard cell potential of the overall reaction is +0.43 V
Answer:- 0.143 M
Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:
Let's calculate the initial moles of HCl and the moles of NaOH added to it:
= 0.075 mol HCl
= 0.025 mol NaOH
Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.
Remaining moles of HCl = 0.075 - 0.025 = 0.050
Total volume of the resulting solution = 0.250 L + 0.100 L = 0.350 L
So, the concentration of HCl in the resulting solution =
= 0.143 M
Hence, the concentration of HCl acid in the resulting solution is 0.143 M.
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"1 x Ca = 1 x 40 = 40
1 x C = 1 x 12 = 12
3 x O = 3 x 16 = 48
40 + 12 + 48 = 100 (Mr of CaCO3)
moles = mass / Mr
mass = moles x Mr
mass = 1 mole x 100 = 100grams."</span><span>
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