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Art [367]
2 years ago
11

How many moles are in 8.5 x 10²⁵ molecules of Carbon Dioxide?

Chemistry
1 answer:
ArbitrLikvidat [17]2 years ago
4 0

Answer:

<h2>141.20 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.5 \times  {10}^{25} }{6.02 \times  {10}^{23} }  \\  = 141.19601...

We have the final answer as

<h3>141.20 moles</h3>

Hope this helps you

You might be interested in
6CO2 + 6 H2O —&gt; C6H12O6 + 6O2
PilotLPTM [1.2K]

Answer:

The answer to your question is 0.5 moles

Explanation:

Data

moles of Glucose = ?

moles of carbon dioxide = 3

Balanced chemical reaction

                6CO₂  +  6H₂O   ⇒   C₆H₁₂O₆  +  6O₂

Process

To solve this problem, use proportions, and cross multiplication.

Use the coefficients of the balanced equation.

                6 moles of CO₂ ----------------- 1 mol of C₆H₁₂O₆

                3 moles of CO₂ ----------------    x

                    x = (3 x 1) / 6

-Simplification

                    x = 3/6

-Result

                   x = 0.5 moles of Glucose

3 0
3 years ago
A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. how much calcium is contained in 45.0 g of c
kolbaska11 [484]

In a sample of pure calcium fluoride of mass 15.0 g, 7.70 g of calcium is present. First convert the mass into number of moles as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass.

Molar mass of Ca is 40 g/mol, putting the values,

n=\frac{7.70 g}{40 g/mol}=0.1925 mol

Similarly, molar mass of CaF_{2} is 78.07 g/mol thus, number of moles will be:

n=\frac{15.0 g}{78.07 g/mol}=0.1921 mol.

Thus, 0.1921 mol of CaF_{2} have 0.1925 mol of Ca, or 1 mole of CaF_{2} will have approximately 1 mole of Ca.

Now, mass of Ca needs to be calculated in 45.0 g of CaF_{2}. Converting mass into number of moles first,

n=\frac{45.0 g}{78.07 g/mol}=0.5764 mol

Thus, number of moles of Ca will also be 0.5764 mol, converting number of moles into mass,

m=n\times M=0.5764 mol\times 40 g/mol=23.06 g

Therefore, mass of Ca will be 23.06 g.

6 0
3 years ago
Your taking a walk in a warm fall morning the temperature is about 70 degrees Fahrenheit and you cannot see a cloud anywhere in
fomenos

Answer:

The relative humidity is low

Explanation:

The higher the dew point rises, the greater the amount of moisture in the air. The lower the humidity, the lower the dew point. The dew point is low and thus water cannot exist in liquid state but as a gas.

8 0
3 years ago
If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?
Ipatiy [6.2K]

It takes 21.3 days

<h3>Further explanation</h3>

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

\tt \dfrac{5000~g}{46~g/mol}=108.7~moles

moles of glucose to produce 108.7 moles ethanol :

\tt \dfrac{1}{2}\times 108.7=54.35

54.35 moles = 5 hours

moles of 1000 kg of glucose :

\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles

So for 5555.5 moles, it takes :

\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days

7 0
3 years ago
What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?
Inessa05 [86]

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

 The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

                           H = 1g/mol

                            N = 14g/mol

                            O = 16g/mol

 Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

                                = 168 + 22 + 56 + 128

                                 = 374u

Empirical weight:

  Empirical formula:

                        C₁₄    H₂₂      N₄     O₈

                         14  :    22 :    4  :     8

   divide by 2:

                          7   :    11    :    2  :    4

     empirical formula  C₇H₁₁N₂O₄

     empirical weight = \frac{molecular weight}{2} = \frac{374}{2} = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

8 0
3 years ago
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