Calculate E∘cell for the following balanced redox reaction: 2Cu(s)+Ca2+(aq)→2Cu+(aq)+Ca(s)
1 answer:
You might be interested in
Explanation:
This is expressing as a subject of a formula of a specie.
This equation is used in solving for specific heat capacity of a material;
equation:
c =
First cross multiply:
c[M(T2 - T1)] = h
Then multiply both sides by :
x c[M(T2 - T1)] =
x h
M(T2 - T1) =
Multiply both sides by
x M(T2 - T1) =
T2 - T1 =
Now rearrange to produce;
T1 = T2 +
learn more:
Specific heat brainly.com/question/7210400
#learnwithBrainly
Answer:
Elemental gold to have a Face-centered cubic structure.
Explanation:
From the information given:
Radius of gold = 144 pm
Its density = 19.32 g/cm³
Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:
a = 407 pm
In a unit cell, Volume (V) = a³
V = (407 pm)³
V = 6.74 × 10⁷ pm³
V = 6.74 × 10⁻²³ cm³
Recall that:
Net no. of an atom in an FCC unit cell = 4
Thus;
density d = 19.41 g/cm³
Similarly; For a body-centered cubic structure
where;
r = 144
a = 332.56 pm
In a unit cell, Volume V = a³
V = (332.56 pm)³
V = 3.68 × 10⁷ pm³
V 3.68 × 10⁻²³ cm³
Recall that:
Net no. of atoms in BCC cell = 2
∴
density =17.78 g/cm³
From the two calculate densities, we will realize that the density in the face-centered cubic structure is closer to the given density.
This makes the elemental gold to have a Face-centered cubic structure.