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Darya [45]
2 years ago
5

What is the hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4.

Chemistry
1 answer:
Maksim231197 [3]2 years ago
4 0

The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7.

pH= -log[H+] - (i)

10^-3=H2So4

H+= 2×10-3

here ,

h2so4 ——— 2[H+] + so4^2-

thus [H+]= 2*10^(-3) because hydrogen ion has two moles

pH= -log[H+]

pH= -log(2×10^-3)

pH= 3-log2

pH= 3-log2pH= 2.7

The pH is 2.7

<h3>What is pH?</h3>

PH is the degree of alkalinity and acidicity in a solution.

Therefore, The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7

Learn more about pH from the link below.

https://brainly.in/question/9937410

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S8 + 12 O2 —&gt; 8 SO3 what volume of oxygen would be required to completely react with 45.7g of S8
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47.9L of oxygen would be required

Explanation:

<em>Assuming oxygen gas is at STP</em>

Based on the reaction:

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To solve this question we must find the moles of S₈ added. With the reaction we can find the moles of O₂ and using PV = nRT we can find the volume of oxygen required:

<em>Moles S₈:</em>

45.7g * (1mol / 256.52g) = 0.178 moles S₈

<em>Moles O₂:</em>

0.178 moles S₈ * (12 moles O₂ / 1mol S₈) = 2.138 moles O₂

<em>Volume O₂:</em>

PV = nRT

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<em>R is gas constant 0.082atmL/molK</em>

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<em>P is pressure = 1 atm at STP</em>

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V = 2.138mol*0.082atmL/molK*273.15K / 1atm

V = 47.9L of oxygen would be required

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