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N76 [4]
4 years ago
6

A sample of hydrogen gas is found to be 8.50 L at a temperature of 38.0 C and a pressure of 725mm Hg. Find the volume at STP.

Chemistry
1 answer:
Vsevolod [243]4 years ago
6 0
Temp must be Kelvin
38 C = <span> <span> <span> 311.15 </span> </span> </span> K
Volume at STP = 8.50 liters * (273.15 / 311.15) * (725 / 760) =
<span> <span> <span> 7.1182746306 </span> </span> </span> Liters

The formula to use is:

Volume at STP = Present Volume * (273.15 / Present Temp °K) * (Present Pressure (Torr) / 760)

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In an atom, only masses of protons and neutrons are relevant. electrons are so small in size that their masses are negligible.

The mass of 1 proton/neutron is 1amu.

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5 0
4 years ago
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Which solution when mixed with a drop ofbromthymol blue will cause the indicator to change from blue to yellow
zheka24 [161]

Answer: A

Explanation: the only way to turn it from blue to yellow is to mix it with an acidic solution.

6 0
3 years ago
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Baker’s yeast catalyzes the decomposition of hydrogen peroxide (dihydrogen dioxide) into oxygen and water. Directions: Add 10 mL
andreev551 [17]

Answer:

The unbalanced chemical equation: H₂O₂ → H₂O + O₂.

The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.

Explanation:

  • Hydrogen peroxide is decomposed into oxygen and water, which is a slow reaction.
  • It is can be catalyzed by using yeast.

The unbalanced chemical equation: H₂O₂ → H₂O + O₂.

The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.

1.0 mol of H₂O₂ is decomposed to 1.0 mol of H₂O and 0.5 mol of O₂.

3 0
4 years ago
When 91.5 g of isopropyl alcohol which has an empirical formula of C3H8O is burned in excess oxygen gas, how many grams of H2O a
Kobotan [32]

Answer:

109.7178g of H2O

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

2C3H8O + 9O2 —> 6CO2 + 8H2O

Next we will calculate the molar mass and masses of C3H8O and H20. This is illustrated below:

Molar Mass of C3H8O = (3x12.011) + (8x1.00794) + 15.9994 = 36.033 + 8.06352 + 15.9994 = 60.09592g/mol.

Mass of C3H8O from the balanced equation = 2 x 60.09592 = 120.19184g

Molar Mass of H2O = (2x1.00794) + 15.9994 = 2.01588 + 15.9994 = 18.01528g/mol

Mass of H2O from the balanced equation = 8 x 18.01528 = 144.12224g

From the equation,

120.19184g of C3H8O produced 144.12224g of H20.

Therefore, 91.5g of C3H8O will produce = (91.5 x 144.12224) /120.19184 = 109.7178g of H2O

7 0
4 years ago
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