The van't Hoff factor is the ratio between the amount of particles produced when a substance is dissolved and the amount of substance being dissolved. If ionization is 0 percent then it would mean that the substance do not dissociate into particles so the van't Hoff factor would be 1. However, when the percent ionization is 100%, then it fully dissociates into ions. For H2SO4 at 100% ionization, the vant hoff factor should be three, two hydrogen ions and one sulfate ion.
Question:
Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the same as pure water at 20.0 degrees C (18 torr). The volume of the mixture is 1.7 L and its total pressure is 0.987 atm. Determine the number of moles of hydrogen gas present in the sample.
A. 0.272 mol
B. 0.04 mol
C. 0.997 mol
D. 0.139 mol
E. 0.0681 mol
Answer:
The correct option is;
E. 0.0681 mol
Explanation:
The equation for the reaction is
Zn + HCl = H₂ + ZnCl₂
Vapor pressure of the liquid = 18 torr = 2399.803 Pa
Total pressure of gas mixture H₂ + liquid vapor = 0.987 atm
= 100007.775 Pa
Therefore, by Avogadro's law, pressure of the hydrogen gas is given by the following equation
Pressure of H₂ = 100007.775 Pa - 2399.803 Pa = 97607.972 Pa
Volume of H₂ = 1.7 L = 0.0017 m³
Temperature = 20 °C = 293.15 K
Therefore,
Therefore, the number of moles of hydrogen gas present in the sample is n ≈ 0.0681 moles.
An alkane is a carbon-based molecule comprised of only single bonds (-), whereas an alkene is comprised of at least one double bond (=). If a molecule has no double bonds, it can be classified as an alkane, but if it has at least one double bond it can no longer be classified as such.
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<em><u>A molecule </u></em><em><u>can </u></em><em><u>possess polar bonds and still be nonpolar.</u></em>
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